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Ch 37: Special Relativity
Young & Freedman Calc - University Physics 15th Edition
Young & Freedman Calc15th EditionUniversity PhysicsISBN: 9780135159552Non è quello che usi tu?Cambia libro di testo
Capitolo 36, Problema 37.15

An observer in frame S′ is moving to the right (+x-direction) at speed u = 0.600c away from a stationary observer in frame S. The observer in S′ measures the speed v′ of a particle moving to the right away from her. What speed v does the observer in S measure for the particle if (a) v′ = 0.400c; (b) v′ = 0.900c; (c) v′ = 0.990c?

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Step 1: Recognize that this problem involves relativistic velocity addition. The formula for relativistic velocity transformation is: vS=vS'+u1+vS'uc2, where vS' is the velocity of the particle as measured in frame S′, u is the relative velocity between frames S and S′, and c is the speed of light.
Step 2: Substitute the given values into the formula. For all parts of the problem, u is given as 0.600c. For part (a), vS' is 0.400c. For part (b), vS' is 0.900c. For part (c), vS' is 0.990c. Plug these values into the formula one at a time.
Step 3: Simplify the numerator of the formula for each case. For example, in part (a), the numerator becomes 0.400c+0.600c, which simplifies to 1.000c. Repeat this process for parts (b) and (c).
Step 4: Simplify the denominator of the formula for each case. For part (a), the denominator becomes 1+0.400c×0.600cc2, which simplifies to 1+0.240. Repeat this process for parts (b) and (c).
Step 5: Divide the simplified numerator by the simplified denominator for each case to find the speed vS as measured by the observer in frame S. This step completes the calculation for each part of the problem.

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