Below is a graph of the function y = csc ( b x ) y=\csc\left(bx\right) y = csc ( b x ) . Determine the value of b .

Welcome back, everyone. So let's give this problem a try. Here we're told below is a graph of the function y is equal to the cosecant of b x, and we're asked to determine the value of b. Now to solve this problem, what I'm first going to do is draw a graph of something I'm a bit more familiar with. Now what I recognize here is that the cosecant is a reciprocal identity, and it's a reciprocal identity to the sine function. So I'm going to draw a graph of y is equal to the sine of b x. Now the way that I can figure out what this graph looks like is by recognizing that the sine function is going to be a wave that starts at the origin, and it's going to have its peaks where we have these curves that point upward, these kind of smiley faces, and it's going to have the valleys where we have these curves that point downward, these kind of frowny faces. So when we have our sine function go up here, it's gonna reach a peak, then it's gonna come down here in valley, then it's going to go through here, and then it's gonna reach another peak there, and then reach another valley right about there. So this is what the sine function looks like. Now what I can see for the sine function is we can start here at the origin, and we go up, and then down on this wave, and then back up, and complete a full period at 3 pi over 2 on the x axis. So what that tells me is that our period for this function is 3 pi over 2. Now the reason that this is helpful to find the period is because the period for a sine function is always going to be 2 pi over b. And since we just figured out that the period is 3pi over 2, I can set 3pi over 2 equal to 2pi over b. And all I need to do from here is solve for b. So what I'm first going to do is multiply both sides of the equation by b. This is going to get the b's to cancel on the right side giving me 3 pi over 2 times b is equal to 2pi. Now from here what I'm going to do is multiply both sides of the equation by 1 over pi. This is going to just allow me to cancel this pi on both sides, because notice that the pi's are going to cancel right there, and the pi's are going to cancel right here. So what we're going to have is 3 over 2 times b is equal to 2. The way that I'm going to solve this problem is I'm going to take both sides of this equation and multiply it by the reciprocal of 3 over 2, which is 2 over 3. Now when I do this, this is going to allow me to cancel the threes right there, and the twos right here, leaving me with just 'b'. And then on the right side of this equation we're going to have 2 times 2, which is 4 divided by 3. So the solution for 'b' is 4 thirds, and that's the answer to this problem. So hope you found this video helpful, thanks for watching.

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11m

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12m

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22m

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10. Graphing Trigonometric Functions

Graphs of Secant and Cosecant Functions

Precalculus

10. Graphing Trigonometric Functions

Graphs of Secant and Cosecant Functions

Problema precedenteProssimo problema

Difficoltà con Precalculus?

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Scelta multipla

Below is a graph of the function $y=$\csc$$\left$(bx$\right$)$ . Determine the value of b.

$b=$\frac$12$

$b=3$

$b=$\frac$43$

$b=$\frac{3\pi}{4}$$

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Problema precedenteProssimo problema

Guida verificata passo dopo passo

The function y = csc(bx) is the reciprocal of the sine function, meaning it has vertical asymptotes where the sine function is zero. These occur at integer multiples of π.

Observe the graph provided. The vertical asymptotes are located at x = π/2, x = 3π/2, and x = 5π/2. This indicates that the period of the function is π.

The period of the function y = csc(bx) is given by the formula Period = 2π/b. Since the period observed from the graph is π, we set up the equation π = 2π/b.

Solve the equation π = 2π/b for b. Divide both sides by π to isolate b, resulting in 1 = 2/b.

Multiply both sides by b to get b = 2. Therefore, the value of b that matches the graph is b = 2.

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