Scelta multiplaIdentify the most helpful first step in verifying the identity.sec3θ=secθ+tan2θcosθ\(\sec\)^3\(\theta\)=\(\sec\)\(\theta\)+\(\frac{\tan^2\theta}{\cos\theta}\)sec3θ=secθ+cosθtan2θ386views1rank
Scelta multiplaIdentify the most helpful first step in verifying the identity.(tan2θsin2θ−1)=sec2θsin2(−θ)\(\left\)(\(\frac{\tan^2\theta}{\sin^2\theta}\)-1\(\right\))=\(\sec\)^2\(\theta\[\sin\)^2\(\left\)(-\(\theta\]\right\))(sin2θtan2θ−1)=sec2θsin2(−θ)402views9rank
Scelta multiplaUse the even-odd identities to evaluate the expression.cos(−θ)−cosθ\(\cos\)\(\left\)(-\(\theta\[\right\))-\(\cos\]\theta\)cos(−θ)−cosθ559views9rank
Scelta multiplaUse the even-odd identities to evaluate the expression.−cot(θ)⋅sin(−θ)-\(\cot\)\(\left\)(\(\theta\[\right\))\(\cdot\]\sin\[\left\)(-\(\theta\]\right\))−cot(θ)⋅sin(−θ)625views16rank
Scelta multiplaSelect the expression with the same value as the given expression.sin(−38°)\(\sin\[\left\)(-38\(\degree\]\right\))sin(−38°)562views11rank
Scelta multiplaUse the Pythagorean identities to rewrite the expression as a single term.(1+cscθ)(1−cscθ)\(\left\)(1+\(\csc\[\theta\]\right\))\(\left\)(1-\(\csc\[\theta\]\right\))(1+cscθ)(1−cscθ)531views15rank
Scelta multiplaUse the Pythagorean identities to rewrite the expression with no fraction.11−secθ\(\frac{1}{1-\sec\theta}\)1−secθ1437views10rank
Scelta multiplaSimplify the expression.tan2θ−sec2θ+1\(\tan\)^2\(\theta\)-\(\sec\)^2\(\theta\)+1tan2θ−sec2θ+1453views7rank