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Ch. 1 - Angles and the Trigonometric Functions
Blitzer - Trigonometry 3rd Edition
Blitzer3rd EditionTrigonometryISBN: 9780137316601Non è quello che usi tu?Cambia libro di testo
Capitolo 1, Problema 27

If θ is an acute angle and sin θ = (2√7) / 7, use the identity sin²θ + cos²θ = 1 to find cos θ.

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Recall the Pythagorean identity for sine and cosine: \(\sin^{2}\theta + \cos^{2}\theta = 1\).
Substitute the given value of \(\sin \theta = \frac{2\sqrt{7}}{7}\) into the identity: \(\left(\frac{2\sqrt{7}}{7}\right)^{2} + \cos^{2}\theta = 1\).
Calculate \(\sin^{2}\theta\) by squaring \(\frac{2\sqrt{7}}{7}\): \(\left(\frac{2\sqrt{7}}{7}\right)^{2} = \frac{4 \times 7}{49} = \frac{28}{49}\).
Rewrite the equation as \(\frac{28}{49} + \cos^{2}\theta = 1\) and solve for \(\cos^{2}\theta\) by subtracting \(\frac{28}{49}\) from both sides.
Since \(\theta\) is acute, take the positive square root of \(\cos^{2}\theta\) to find \(\cos \theta\).

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