Domanda del libro di testo
In Exercises 25–28, use each graph to obtain the graph of the corresponding reciprocal function, cosecant or secant. Give the equation of the function for the graph that you obtain.
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Ch. 2 - Graphs of the Trigonometric Functions; Inverse Trigonometric Functions
Blitzer3rd EditionTrigonometryISBN: 9780137316601
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Blitzer 3rd EditionCh. 2 - Graphs of the Trigonometric Functions; Inverse Trigonometric FunctionsProblema 26
Blitzer 3rd EditionCh. 2 - Graphs of the Trigonometric Functions; Inverse Trigonometric FunctionsProblema 26Capitolo 2, Problema 26
In Exercises 21–28, an object moves in simple harmonic motion described by the given equation, where t is measured in seconds and d in inches. In each exercise, find the following: a. the maximum displacement b. the frequency c. the time required for one cycle. d = 1/3 sin 2t
Guida verificata passo dopo passo1
Identify the given simple harmonic motion equation: \(d = \frac{1}{3} \sin 2t\), where \(d\) is displacement and \(t\) is time in seconds.
To find the maximum displacement, recognize that the amplitude of the sine function represents the maximum displacement. The amplitude is the coefficient in front of the sine function, which is \(\frac{1}{3}\) inches.
To find the frequency, recall that the general form of simple harmonic motion is \(d = A \sin(\omega t)\), where \(\omega\) is the angular frequency in radians per second. Here, \(\omega = 2\). Use the relationship between angular frequency and frequency: \(f = \frac{\omega}{2\pi}\).
To find the time required for one cycle (the period \(T\)), use the formula \(T = \frac{1}{f}\) or equivalently \(T = \frac{2\pi}{\omega}\). Since \(\omega = 2\), substitute this value to find \(T\).
Summarize the results: maximum displacement is the amplitude \(\frac{1}{3}\) inches, frequency is \(\frac{2}{2\pi}\) Hz, and period is \(\frac{2\pi}{2}\) seconds.
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Simple Harmonic Motion (SHM)
Simple Harmonic Motion describes oscillatory motion where the restoring force is proportional to displacement and acts in the opposite direction. The displacement varies sinusoidally with time, typically expressed as d(t) = A sin(ωt + φ), where A is amplitude, ω is angular frequency, and φ is phase shift.
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04:46
Products of Complex Numbers in Polar Form
Amplitude and Maximum Displacement
Amplitude is the maximum displacement from the equilibrium position in SHM. It represents the peak value of the sinusoidal function and determines how far the object moves from its central position. In the equation d = (1/3) sin 2t, the amplitude is 1/3 inches.
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5:05Amplitude and Reflection of Sine and Cosine
Frequency and Period of Oscillation
Frequency is the number of complete cycles per second, measured in Hertz (Hz), and is related to angular frequency ω by f = ω/(2π). The period is the time for one full cycle, given by T = 1/f. For d = (1/3) sin 2t, ω = 2, so frequency and period can be calculated accordingly.
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5:33Period of Sine and Cosine Functions
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Domanda del libro di testo
Use each graph to obtain the graph of the corresponding reciprocal function, cosecant or secant. Give the equation of the function for the graph that you obtain.
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In Exercises 1–26, find the exact value of each expression. _ sec⁻¹ (−√2)
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