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Ch. 3 - Trigonometric Identities and Equations
Blitzer - Trigonometry 3rd Edition
Blitzer3rd EditionTrigonometryISBN: 9780137316601Non è quello che usi tu?Cambia libro di testo
Capitolo 3, Problema 3.5.51

Exercises 39–52 involve trigonometric equations quadratic in form. Solve each equation on the interval [0, 2𝝅). sec² x - 2 = 0

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Recall the identity relating secant and cosine: \(\sec x = \frac{1}{\cos x}\), so \(\sec^2 x = \frac{1}{\cos^2 x}\).
Rewrite the given equation \(\sec^2 x - 2 = 0\) in terms of cosine: \(\frac{1}{\cos^2 x} - 2 = 0\).
Isolate the term with cosine: \(\frac{1}{\cos^2 x} = 2\), then take the reciprocal to get \(\cos^2 x = \frac{1}{2}\).
Take the square root of both sides to find \(\cos x = \pm \frac{1}{\sqrt{2}}\), remembering to consider both positive and negative roots.
Determine all values of \(x\) in the interval \([0, 2\pi)\) where \(\cos x = \frac{1}{\sqrt{2}}\) and \(\cos x = -\frac{1}{\sqrt{2}}\), using the unit circle or cosine values.

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