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Ch. 3 - Trigonometric Identities and Equations
Blitzer - Trigonometry 3rd Edition
Blitzer3rd EditionTrigonometryISBN: 9780137316601Non è quello che usi tu?Cambia libro di testo
Capitolo 3, Problema 16

Verify each identity. cos² θ (1 + tan² θ) = 1

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Recall the Pythagorean identity involving tangent and secant: \(\tan^{2} \theta + 1 = \sec^{2} \theta\).
Rewrite the expression \(\cos^{2} \theta (1 + \tan^{2} \theta)\) by substituting \(1 + \tan^{2} \theta\) with \(\sec^{2} \theta\), so it becomes \(\cos^{2} \theta \cdot \sec^{2} \theta\).
Express \(\sec \theta\) in terms of cosine: \(\sec \theta = \frac{1}{\cos \theta}\), so \(\sec^{2} \theta = \frac{1}{\cos^{2} \theta}\).
Substitute \(\sec^{2} \theta\) back into the expression to get \(\cos^{2} \theta \cdot \frac{1}{\cos^{2} \theta}\).
Simplify the expression by canceling \(\cos^{2} \theta\) in numerator and denominator, which results in \(1\), thus verifying the identity.

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