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Ch. 3 - Trigonometric Identities and Equations
Blitzer - Trigonometry 3rd Edition
Blitzer3rd EditionTrigonometryISBN: 9780137316601Non è quello che usi tu?Cambia libro di testo
Capitolo 3, Problema 3.RE.35e

In Exercises 35–38, find the exact value of the following under the given conditions:
e. cos(β/2)
sin α = 3/5, 0 < α < 𝝅/2, and sin β = 12/13, 𝝅/2 < β < 𝝅.

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Identify the given information: \( \sin \alpha = \frac{3}{5} \) with \( 0 < \alpha < \frac{\pi}{2} \), and \( \sin \beta = \frac{12}{13} \) with \( \frac{\pi}{2} < \beta < \pi \).
Since \( \alpha \) is in the first quadrant (between 0 and \( \frac{\pi}{2} \)), both \( \sin \alpha \) and \( \cos \alpha \) are positive. Use the Pythagorean identity to find \( \cos \alpha \): \(\cos \alpha = \sqrt{1 - \sin^2 \alpha} = \sqrt{1 - \left(\frac{3}{5}\right)^2}\)
Since \( \beta \) is in the second quadrant (between \( \frac{\pi}{2} \) and \( \pi \)), \( \sin \beta \) is positive but \( \cos \beta \) is negative. Use the Pythagorean identity to find \( \cos \beta \): \(\cos \beta = -\sqrt{1 - \sin^2 \beta} = -\sqrt{1 - \left(\frac{12}{13}\right)^2}\)
Use the cosine of difference formula to find \( \cos(\beta - \alpha) \): \(\cos(\beta - \alpha) = \cos \beta \cos \alpha + \sin \beta \sin \alpha\)
Substitute the values of \( \cos \alpha \), \( \cos \beta \), \( \sin \alpha \), and \( \sin \beta \) into the formula and simplify to find the exact value of \( \cos(\beta - \alpha) \).

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