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Ch. 3 - Trigonometric Identities and Equations
Blitzer - Trigonometry 3rd Edition
Blitzer3rd EditionTrigonometryISBN: 9780137316601Non è quello che usi tu?Cambia libro di testo
Capitolo 3, Problema 3.5.57

In Exercises 53–62, solve each equation on the interval [0, 2𝝅). cot x (tan x - 1) = 0

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Start by analyzing the given equation: \(\cot x (\tan x - 1) = 0\). Since this is a product equal to zero, use the zero product property which states that if $AB = 0$, then either \(A = 0\) or \(B = 0\).
Set each factor equal to zero separately: 1) \(\cot x = 0\) 2) \(\tan x - 1 = 0\)
Solve the first equation \(\cot x = 0\). Recall that \(\cot x = \frac{\cos x}{\sin x}\), so \(\cot x = 0\) when \(\cos x = 0\) (and \(\sin x \neq 0\)). Find all \(x\) in \([0, 2\pi)\) where \(\cos x = 0\).
Solve the second equation \(\tan x - 1 = 0\) which simplifies to \(\tan x = 1\). Find all \(x\) in \([0, 2\pi)\) where the tangent of \(x\) equals 1.
Combine all solutions from both equations and ensure they lie within the interval \([0, 2\pi)\). These combined values of \(x\) will be the solutions to the original equation.

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The zero-product property states that if a product of two factors equals zero, then at least one of the factors must be zero. This principle allows us to split the equation cot x (tan x - 1) = 0 into two simpler equations: cot x = 0 and tan x - 1 = 0, which can be solved separately.
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