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Ch. 3 - Trigonometric Identities and Equations
Blitzer - Trigonometry 3rd Edition
Blitzer3rd EditionTrigonometryISBN: 9780137316601Non è quello che usi tu?Cambia libro di testo
Capitolo 3, Problema 3.5.53

In Exercises 53–62, solve each equation on the interval [0, 2𝝅). (tan x - 1) (cos x + 1) = 0

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Recognize that the equation is a product of two factors equal to zero: \((\tan x - 1)(\cos x + 1) = 0\). According to the zero product property, set each factor equal to zero separately: \(\tan x - 1 = 0\) and \(\cos x + 1 = 0\).
Solve the first equation \(\tan x - 1 = 0\) which simplifies to \(\tan x = 1\). Recall that \(\tan x = 1\) at angles where the sine and cosine are equal in magnitude and sign, specifically in the first and third quadrants within \([0, 2\pi)\).
Find the general solutions for \(\tan x = 1\) on the interval \([0, 2\pi)\), which correspond to \(x = \frac{\pi}{4}\) and \(x = \frac{5\pi}{4}\).
Solve the second equation \(\cos x + 1 = 0\) which simplifies to \(\cos x = -1\). Recall that cosine equals \(-1\) at the angle where the terminal side points directly to the left on the unit circle.
Find the solution for \(\cos x = -1\) on the interval \([0, 2\pi)\), which is \(x = \pi\). Combine all solutions from both equations to get the complete solution set.

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Zero Product Property

The zero product property states that if the product of two factors equals zero, then at least one of the factors must be zero. This allows the equation (tan x - 1)(cos x + 1) = 0 to be split into two simpler equations: tan x - 1 = 0 and cos x + 1 = 0.
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