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Ch. 3 - Trigonometric Identities and Equations
Blitzer - Trigonometry 3rd Edition
Blitzer3rd EditionTrigonometryISBN: 9780137316601Non è quello che usi tu?Cambia libro di testo
Capitolo 3, Problema 75

In Exercises 63–84, use an identity to solve each equation on the interval [0, 2𝝅). sin x cos x = √ 2 / 4

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1
Start with the given equation: \(\sin x \cos x = \frac{\sqrt{2}}{4}\).
Recall the double-angle identity for sine: \(\sin(2x) = 2 \sin x \cos x\). Use this to rewrite the left side of the equation.
Multiply both sides of the equation by 2 to express it in terms of \(\sin(2x)\): \(2 \sin x \cos x = 2 \times \frac{\sqrt{2}}{4}\), which simplifies to \(\sin(2x) = \frac{\sqrt{2}}{2}\).
Solve the equation \(\sin(2x) = \frac{\sqrt{2}}{2}\) for \$2x$ on the interval \([0, 4\pi)\), since $x$ is in \([0, 2\pi)\) and the argument is \$2x$.
Find all values of \(x\) by dividing the solutions for \$2x$ by 2, ensuring the solutions fall within the original interval \([0, 2\pi)\).

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