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Ch. 3 - Trigonometric Identities and Equations
Blitzer - Trigonometry 3rd Edition
Blitzer3rd EditionTrigonometryISBN: 9780137316601Non è quello che usi tu?Cambia libro di testo
Capitolo 3, Problema 9c

Use the given information to find the exact value of each of the following: tan2θ\(\tan\)2\(\theta\)
cosθ=2425,θ lies in quadrant IV.\(\cos\) \(\theta\) = \(\frac{24}{25}\), \(\quad\) \(\theta\) \(\text{ lies in quadrant IV.}\)

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1
Identify the given information: \(\cos \theta = \frac{24}{25}\) and \(\theta\) lies in quadrant IV. Recall that in quadrant IV, cosine is positive and sine is negative.
Use the Pythagorean identity to find \(\sin \theta\): \(\sin^2 \theta + \cos^2 \theta = 1\). Substitute \(\cos \theta = \frac{24}{25}\) to find \(\sin \theta\).
Calculate \(\sin \theta\) by rearranging the identity: \(\sin \theta = -\sqrt{1 - \left(\frac{24}{25}\right)^2}\), taking the negative root because \(\sin \theta\) is negative in quadrant IV.
Use the double-angle formula for tangent: \(\tan 2\theta = \frac{2 \tan \theta}{1 - \tan^2 \theta}\). To apply this, first find \(\tan \theta = \frac{\sin \theta}{\cos \theta}\).
Substitute \(\tan \theta\) into the double-angle formula to express \(\tan 2\theta\) in terms of known values, then simplify the expression to find the exact value.

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The double-angle identity for tangent states that tan(2θ) = (2 tan θ) / (1 - tan² θ). This formula allows you to find the tangent of twice an angle using the tangent of the original angle, which is essential for solving the problem once tan θ is known.
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