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Ch. 4 - Laws of Sines and Cosines; Vectors
Blitzer - Trigonometry 3rd Edition
Blitzer3rd EditionTrigonometryISBN: 9780137316601Non è quello che usi tu?Cambia libro di testo
Capitolo 4, Problema 36

In Exercises 33–38, find the area of the triangle having the given measurements. Round to the nearest square unit.
B = 125°, a = 8 yards, c = 5 yards

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Identify the given elements of the triangle: angle \(B = 125^\circ\), side \(a = 8\) yards (opposite angle \(A\)), and side \(c = 5\) yards (opposite angle \(C\)).
Use the Law of Cosines to find the length of side \(b\) (opposite angle \(B\)) since you know two sides and the included angle \(B\). The Law of Cosines formula is: \[b^2 = a^2 + c^2 - 2 \times a \times c \times \cos(B)\]
Calculate \(b\) by taking the square root of the result from the Law of Cosines: \[b = \sqrt{a^2 + c^2 - 2ac \cos(B)}\]
Use the Law of Sines to find one of the other angles, for example angle \(A\), using the formula: \[\frac{\sin(A)}{a} = \frac{\sin(B)}{b}\] Rearranged to solve for \(\sin(A)\): \[\sin(A) = \frac{a \times \sin(B)}{b}\]
Finally, find the area of the triangle using the formula involving two sides and the included angle: \[\text{Area} = \frac{1}{2} \times a \times c \times \sin(B)\] This formula directly uses the two known sides and the included angle to find the area.

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