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Ch. 2 - Acute Angles and Right Triangles
Lial - Trigonometry 12th Edition
Lial12th EditionTrigonometryISBN: 9780136552161, 9780135440780, 9780136881117, 9780135440827, 9780135924891Non è quello che usi tu?Cambia libro di testo
Capitolo 3, Problema 31

Find one solution for each equation. Assume all angles involved are acute angles. See Example 3. tan α = cot(α + 10°)

Guida verificata passo dopo passo
1
Recall the definition of cotangent in terms of tangent: \(\cot \theta = \frac{1}{\tan \theta}\). So, rewrite the equation \(\tan \alpha = \cot(\alpha + 10^\circ)\) as \(\tan \alpha = \frac{1}{\tan(\alpha + 10^\circ)}\).
Multiply both sides of the equation by \(\tan(\alpha + 10^\circ)\) to eliminate the fraction: \(\tan \alpha \cdot \tan(\alpha + 10^\circ) = 1\).
Use the tangent addition formula to express \(\tan(\alpha + 10^\circ)\) in terms of \(\tan \alpha\) and \(\tan 10^\circ\): \(\tan(\alpha + 10^\circ) = \frac{\tan \alpha + \tan 10^\circ}{1 - \tan \alpha \tan 10^\circ}\).
Substitute this expression back into the equation from step 2: \(\tan \alpha \cdot \frac{\tan \alpha + \tan 10^\circ}{1 - \tan \alpha \tan 10^\circ} = 1\).
Multiply both sides by the denominator to clear the fraction and then rearrange the resulting equation to form a quadratic equation in terms of \(\tan \alpha\). Solve this quadratic equation to find possible values of \(\tan \alpha\), and then determine \(\alpha\) by taking the arctangent, considering that \(\alpha\) is an acute angle.

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