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Ch. 3 - Radian Measure and The Unit Circle
Lial - Trigonometry 12th Edition
Lial12th EditionTrigonometryISBN: 9780136552161, 9780135440780, 9780136881117, 9780135440827, 9780135924891Non è quello che usi tu?Cambia libro di testo
Capitolo 4, Problema 63

Find the approximate value of s, to four decimal places, in the interval [0, π/2] that makes each statement true.


sin s = 0.9918

Guida verificata passo dopo passo
1
Identify the problem: We need to find the value of \( s \) in the interval \( [0, \frac{\pi}{2}] \) such that \( \sin s = 0.9918 \).
Recall that to find an angle \( s \) given \( \sin s = a \), we use the inverse sine function (also called arcsine), denoted as \( \sin^{-1} \) or \( \arcsin \). So, \( s = \arcsin(0.9918) \).
Make sure the value \( 0.9918 \) is within the valid range for sine, which is \( [-1, 1] \). Since it is, the inverse sine function is defined.
Calculate \( s = \arcsin(0.9918) \) using a calculator set to radians mode to get the angle in radians.
Round the result to four decimal places to get the approximate value of \( s \) within the interval \( [0, \frac{\pi}{2}] \).

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Sine Function and Its Range

The sine function relates an angle in a right triangle to the ratio of the opposite side over the hypotenuse. Its values range between -1 and 1, and within the interval [0, π/2], sine values increase from 0 to 1. Understanding this helps identify valid solutions for the equation sin s = 0.9918.
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Domain and Range of Function Transformations

Inverse Sine Function (Arcsin)

The inverse sine function, denoted as arcsin or sin⁻¹, returns the angle whose sine is a given value. It is used to find the angle s when sin s is known. Since arcsin outputs values in [-π/2, π/2], restricting the domain to [0, π/2] ensures a unique solution for s.
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Radian Measure and Interval Constraints

Angles in trigonometry are often measured in radians, where π radians equal 180 degrees. The interval [0, π/2] corresponds to angles from 0 to 90 degrees, representing the first quadrant where sine values are positive and increasing. This constraint limits the solution to a specific range.
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Converting between Degrees & Radians