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Ch. 6 - Inverse Circular Functions and Trigonometric Equations
Lial - Trigonometry 12th Edition
Lial12th EditionTrigonometryISBN: 9780136552161, 9780135440780, 9780136881117, 9780135440827, 9780135924891Non è quello che usi tu?Cambia libro di testo
Capitolo 7, Problema 31

Evaluate each expression without using a calculator.
cos (csc⁻¹ (-2))

Guida verificata passo dopo passo
1
Recognize that the expression involves the inverse cosecant function: \(\csc^{-1}(-2)\). Let \(\theta = \csc^{-1}(-2)\), which means \(\csc \theta = -2\).
Recall the definition of cosecant: \(\csc \theta = \frac{1}{\sin \theta}\). From \(\csc \theta = -2\), we get \(\sin \theta = \frac{1}{-2} = -\frac{1}{2}\).
Determine the quadrant where \(\theta\) lies. Since \(\csc^{-1} x\) typically returns values in \([-\frac{\pi}{2}, 0) \cup (0, \frac{\pi}{2}]\) excluding zero, and \(\sin \theta = -\frac{1}{2}\) is negative, \(\theta\) must be in the fourth quadrant.
Use the Pythagorean identity to find \(\cos \theta\): \(\cos \theta = \pm \sqrt{1 - \sin^2 \theta} = \pm \sqrt{1 - \left(-\frac{1}{2}\right)^2} = \pm \sqrt{1 - \frac{1}{4}} = \pm \sqrt{\frac{3}{4}} = \pm \frac{\sqrt{3}}{2}\).
Determine the sign of \(\cos \theta\) in the fourth quadrant. Since cosine is positive in the fourth quadrant, \(\cos \theta = \frac{\sqrt{3}}{2}\). Therefore, \(\cos(\csc^{-1}(-2)) = \frac{\sqrt{3}}{2}\).

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