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Ch. 6 - Inverse Circular Functions and Trigonometric Equations
Lial - Trigonometry 12th Edition
Lial12th EditionTrigonometryISBN: 9780136552161, 9780135440780, 9780136881117, 9780135440827, 9780135924891Non è quello che usi tu?Cambia libro di testo
Capitolo 7, Problema 29

Evaluate each expression without using a calculator.
sin (arccos (3/4))

Guida verificata passo dopo passo
1
Recognize that the expression is \( \sin(\arccos(\frac{3}{4})) \). Here, \( \arccos(\frac{3}{4}) \) represents an angle \( \theta \) such that \( \cos \theta = \frac{3}{4} \).
Draw a right triangle to visualize the angle \( \theta \). Since \( \cos \theta = \frac{3}{4} \), the adjacent side to \( \theta \) is 3 and the hypotenuse is 4.
Use the Pythagorean theorem to find the opposite side: \( \text{opposite} = \sqrt{4^2 - 3^2} = \sqrt{16 - 9} \).
Calculate \( \sin \theta \) using the definition \( \sin \theta = \frac{\text{opposite}}{\text{hypotenuse}} \). Substitute the values found for the opposite side and hypotenuse.
Write the final expression for \( \sin(\arccos(\frac{3}{4})) \) as \( \frac{\sqrt{16 - 9}}{4} \), which simplifies the problem without using a calculator.

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Inverse Trigonometric Functions

Inverse trigonometric functions, like arccos, return the angle whose trigonometric ratio matches a given value. For example, arccos(3/4) gives the angle whose cosine is 3/4. Understanding this helps translate the expression into a geometric or algebraic problem.
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Introduction to Inverse Trig Functions

Pythagorean Identity

The Pythagorean identity states that sin²θ + cos²θ = 1 for any angle θ. This relationship allows us to find the sine of an angle if we know its cosine, by rearranging to sinθ = √(1 - cos²θ). This is essential for evaluating sin(arccos(3/4)) without a calculator.
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Pythagorean Identities

Evaluating Composite Trigonometric Expressions

Evaluating expressions like sin(arccos(x)) involves substituting the inner function with an angle and then applying trigonometric identities. This process often uses right triangle interpretations or algebraic manipulation to find exact values without numerical approximation.
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Evaluate Composite Functions - Special Cases