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Ch. 6 - Inverse Circular Functions and Trigonometric Equations
Lial - Trigonometry 12th Edition
Lial12th EditionTrigonometryISBN: 9780136552161, 9780135440780, 9780136881117, 9780135440827, 9780135924891Non è quello che usi tu?Cambia libro di testo
Capitolo 7, Problema 6.3.45

Solve each equation (x in radians and θ in degrees) for all exact solutions where appropriate. Round approximate answers in radians to four decimal places and approximate answers in degrees to the nearest tenth. Write answers using the least possible nonnegative angle measures.


3 csc² x/2 = 2 sec x

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1
Rewrite the given equation \(3 \csc^{2} \frac{x}{2} = 2 \sec x\) in terms of sine and cosine functions. Recall that \(\csc \theta = \frac{1}{\sin \theta}\) and \(\sec \theta = \frac{1}{\cos \theta}\), so the equation becomes \(3 \left(\frac{1}{\sin^{2} \frac{x}{2}}\right) = 2 \left(\frac{1}{\cos x}\right)\).
Multiply both sides of the equation by \(\sin^{2} \frac{x}{2} \cos x\) to clear the denominators, resulting in an equation involving \(\cos x\) and \(\sin^{2} \frac{x}{2}\) without fractions.
Use the double-angle identity for cosine: \(\cos x = 1 - 2 \sin^{2} \frac{x}{2}\), to express \(\cos x\) in terms of \(\sin^{2} \frac{x}{2}\). Substitute this into the equation to have a single trigonometric function variable.
Let \(t = \sin^{2} \frac{x}{2}\) and rewrite the equation as a polynomial in \(t\). Solve this polynomial equation for \(t\) to find possible values of \(\sin^{2} \frac{x}{2}\).
For each valid solution of \(t\), find \(\sin \frac{x}{2}\) and then solve for \(x\) by considering the general solutions for sine. Remember to express \(x\) in radians within the least possible nonnegative angle measures, and also convert to degrees if required, rounding as specified.

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Understanding angle measures in radians and degrees is essential, as problems may require answers in either unit. Converting between radians and degrees (180° = π radians) and expressing solutions within the least nonnegative angle ensures clarity and correctness in final answers.
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