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Ch. 7 - Applications of Trigonometry and Vectors
Lial - Trigonometry 12th Edition
Lial12th EditionTrigonometryISBN: 9780136552161, 9780135440780, 9780136881117, 9780135440827, 9780135924891Non è quello che usi tu?Cambia libro di testo
Capitolo 8, Problema 53

Find the area of each triangle ABC.


B = 124.5°, a = 30.4 cm, c = 28.4 cm

Guida verificata passo dopo passo
1
Identify the given elements: angle \(B = 124.5^\circ\), side \(a = 30.4\) cm (opposite angle \(A\)), and side \(c = 28.4\) cm (opposite angle \(C\)). We need to find the area of triangle \(ABC\).
Recall the formula for the area of a triangle using two sides and the included angle: \(\text{Area} = \frac{1}{2} \times b \times c \times \sin A\), where \(b\) and \(c\) are sides enclosing angle \(A\). Since we have angle \(B\), we can use the formula \(\text{Area} = \frac{1}{2} \times a \times c \times \sin B\) because sides \(a\) and \(c\) enclose angle \(B\).
Substitute the known values into the area formula: \(\text{Area} = \frac{1}{2} \times 30.4 \times 28.4 \times \sin 124.5^\circ\).
Calculate \(\sin 124.5^\circ\) using a calculator or trigonometric tables to find the sine of the given angle.
Multiply the values together: half of the product of sides \(a\) and \(c\), and the sine of angle \(B\) to find the area of triangle \(ABC\).

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