Skip to main content
Ch. R - Algebra Review
Lial - Trigonometry 12th Edition
Lial12th EditionTrigonometryISBN: 9780136552161, 9780135440780, 9780136881117, 9780135440827, 9780135924891Non è quello che usi tu?Cambia libro di testo
Capitolo 1, Problema 19

Find the domain of each rational expression. See Example 1. (x³ - 1) / (x - 1)

Guida verificata passo dopo passo
1
Identify the rational expression given: \(\frac{x^{3} - 1}{x - 1}\).
Recall that the domain of a rational expression includes all real numbers except those that make the denominator zero.
Set the denominator equal to zero and solve for \(x\): \(x - 1 = 0\) which gives \(x = 1\).
Exclude \(x = 1\) from the domain because it makes the denominator zero and the expression undefined.
Therefore, the domain is all real numbers except \(x = 1\), which can be written as \(\{x \in \mathbb{R} \mid x \neq 1\}\).

Risposta video verificata per un problema simile:

Questa soluzione video è stata consigliata dai nostri tutor come utile per risolvere questo problema.
Durata del video:
2m

Concetti chiave

Ecco i concetti essenziali che devi comprendere per rispondere correttamente alla domanda.

Domain of a Rational Expression

The domain of a rational expression includes all real numbers except those that make the denominator zero. Since division by zero is undefined, identifying values that cause the denominator to be zero is essential to determine the domain.
Video consigliato:
Percorso guidato
2:58
Rationalizing Denominators

Factoring Polynomials

Factoring polynomials helps simplify expressions and identify common factors. For example, the numerator x³ - 1 can be factored using the difference of cubes formula, which aids in simplifying the expression and analyzing the domain.
Video consigliato:

Difference of Cubes Formula

The difference of cubes formula states that a³ - b³ = (a - b)(a² + ab + b²). Applying this to x³ - 1 allows factoring the numerator as (x - 1)(x² + x + 1), which is useful for simplifying the rational expression and understanding restrictions on the domain.
Video consigliato:
Percorso guidato
2:25
Verifying Identities with Sum and Difference Formulas