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Ch. 3 - Derivatives
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243당신이 사용하는 게 아니라요?교과서 변경
3장, 문제 73a

Find an equation of the line tangent to the following curves at the given value of x.
y = 1+2 sin x; x = π/6

검증된 단계별 안내
1
First, identify the function for which we need to find the tangent line. The function given is \( y = 1 + 2 \sin x \).
To find the equation of the tangent line, we need the slope of the tangent line at \( x = \frac{\pi}{6} \). This requires finding the derivative of the function, \( y = 1 + 2 \sin x \).
Differentiate the function with respect to \( x \). The derivative of \( y = 1 + 2 \sin x \) is \( y' = 2 \cos x \).
Evaluate the derivative at \( x = \frac{\pi}{6} \) to find the slope of the tangent line. Substitute \( x = \frac{\pi}{6} \) into \( y' = 2 \cos x \) to get the slope.
Finally, use the point-slope form of the equation of a line, \( y - y_1 = m(x - x_1) \), where \( m \) is the slope found in the previous step and \( (x_1, y_1) \) is the point on the curve at \( x = \frac{\pi}{6} \). Calculate \( y_1 \) by substituting \( x = \frac{\pi}{6} \) into the original function \( y = 1 + 2 \sin x \).

비슷한 문제에 대한 검증된 영상 답변:

이 영상 해법은 위 문제에 도움이 된다고 튜터들이 추천한 것입니다.
영상 길이:
5m

주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Tangent Line

A tangent line to a curve at a given point is a straight line that touches the curve at that point without crossing it. The slope of the tangent line represents the instantaneous rate of change of the function at that point, which can be found using the derivative of the function.
추천 영상:
가이드 코스
05:13
Slopes of Tangent Lines

Derivative

The derivative of a function measures how the function's output value changes as its input value changes. It is defined as the limit of the average rate of change of the function over an interval as the interval approaches zero. For the function y = 1 + 2 sin x, the derivative will provide the slope of the tangent line at any point x.
추천 영상:

Evaluating Functions

Evaluating a function involves substituting a specific value into the function to find the corresponding output. In this case, to find the equation of the tangent line at x = π/6, we need to evaluate both the function and its derivative at this point to determine the y-coordinate and the slope of the tangent line.
추천 영상:
가이드 코스
4:26
Evaluating Composed Functions
관련 실천
교과서 질문

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b. Find an equation of the line tangent to y = h(x) at x=2.

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교과서 질문

The right-sided and left-sided derivatives of a function at a point aa are given by f+′(a)=limh→0+f(a+h)−f(a)hf_{+}^{\(\prime\)}\(\left\)(a\(\right\))={\(\displaystyle\)\(\lim\)_{h\(\to\)0^{+}}{\(\frac{f(a+h)-f(a)}{h}\)}} and f−′(a)=limh→0−f(a+h)−f(a)hf_{-}^{\(\prime\)}\(\left\)(a\(\right\))={\(\displaystyle\)\(\lim\)_{h\(\to\)0^{-}}{\(\frac{f(a+h)-f(a)}{h}\)}}, respectively, provided these limits exist. The derivative f′(a)f^{\(\prime\)}\(\left\)(a\(\right\)) exists if and only if f+′(a)=f−′(a)f_{+}^{\(\prime\)}\(\left\)(a\(\right\))=f_{-}^{\(\prime\)}\(\left\)(a\(\right\)).

Compute f+′(a)f_{+}^{\(\prime\)}\(\left\)(a\(\right\)) and f−′(a)f_{-}^{\(\prime\)}\(\left\)(a\(\right\)) at the given point aa.

f(x)={4−x2 if x≤12x+1 if x>1f(x)=\(\begin{cases}\)4-x^2~\(\text{if}\)~x\(\leq{1}\)\\2x+1~\(\text{if}\)~x\(\gt{1}\)\(\end{cases}\); a=1a=1

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교과서 질문

Calculate the derivative of the following functions.

y = (p+3)² sin p²

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교과서 질문

27–76. Calculate the derivative of the following functions.

y = √f(x), where f is differentiable and nonnegative at x.

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교과서 질문

First and second derivatives Find f′(x),f′′(x).

f(x) = x/x+2

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교과서 질문

Suppose f(3) = 1 and f′(3) = 4. Let g(x) = x2 + f(x) and h(x) = 3f(x).

Find an equation of the line tangent to y = g(x) at x = 3.

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