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Ch. 5 - Integration
5์žฅ, ๋ฌธ์ œ 5.3.51d

Properties of integrals Use only the fact that โˆซโ‚€โด 3๐“ (4 โ€•๐“) d๐“ = 32, and the definitions and properties of integrals, to evaluate the following integrals, if possible.
(d) โˆซโ‚€โธ 3๐“(4 โ€• ๐“) d(๐“)

๊ฒ€์ฆ๋œ ๋‹จ๊ณ„๋ณ„ ์•ˆ๋‚ด
1
Step 1: Recognize that the integral โˆซโ‚€โธ 3๐“(4 โ€• ๐“) d๐“ can be split into two parts: โˆซโ‚€โด 3๐“(4 โ€• ๐“) d๐“ and โˆซโ‚„โธ 3๐“(4 โ€• ๐“) d๐“, based on the interval of integration.
Step 2: Use the given information that โˆซโ‚€โด 3๐“(4 โ€• ๐“) d๐“ = 32 to evaluate the first part of the integral.
Step 3: For the second part, โˆซโ‚„โธ 3๐“(4 โ€• ๐“) d๐“, consider the symmetry of the function 3๐“(4 โ€• ๐“). Analyze whether the function changes sign or remains symmetric over the interval [4, 8].
Step 4: If the function is symmetric and the integral over [0, 4] is known, use properties of symmetry to determine the integral over [4, 8]. Alternatively, compute โˆซโ‚„โธ 3๐“(4 โ€• ๐“) d๐“ directly by substitution or other methods.
Step 5: Combine the results of the two integrals, โˆซโ‚€โด 3๐“(4 โ€• ๐“) d๐“ and โˆซโ‚„โธ 3๐“(4 โ€• ๐“) d๐“, to find the value of โˆซโ‚€โธ 3๐“(4 โ€• ๐“) d๐“.

๋น„์Šทํ•œ ๋ฌธ์ œ์— ๋Œ€ํ•œ ๊ฒ€์ฆ๋œ ์˜์ƒ ๋‹ต๋ณ€:

์ด ์˜์ƒ ํ•ด๋ฒ•์€ ์œ„ ๋ฌธ์ œ์— ๋„์›€์ด ๋œ๋‹ค๊ณ  ํŠœํ„ฐ๋“ค์ด ์ถ”์ฒœํ•œ ๊ฒƒ์ž…๋‹ˆ๋‹ค.
์˜์ƒ ๊ธธ์ด:
4m

์ฃผ์š” ๊ฐœ๋…

์งˆ๋ฌธ์— ์˜ฌ๋ฐ”๋ฅด๊ฒŒ ๋‹ตํ•˜๊ธฐ ์œ„ํ•ด ๋ฐ˜๋“œ์‹œ ์ดํ•ดํ•ด์•ผ ํ•˜๋Š” ํ•ต์‹ฌ ๊ฐœ๋…๋“ค์€ ๋‹ค์Œ๊ณผ ๊ฐ™์Šต๋‹ˆ๋‹ค.

Definite Integrals

A definite integral represents the signed area under a curve between two specified limits. It is denoted as โˆซโ‚แต‡ f(x) dx, where 'a' and 'b' are the lower and upper limits, respectively. The value of a definite integral can be interpreted as the accumulation of quantities, such as area, over the interval [a, b].
์ถ”์ฒœ ์˜์ƒ:
๊ฐ€์ด๋“œ ์ฝ”์Šค
05:43
Definition of the Definite Integral

Properties of Integrals

The properties of integrals include linearity, additivity, and the ability to change limits. For instance, the integral of a sum is the sum of the integrals, and the integral from a to b can be expressed as the negative of the integral from b to a. These properties allow for simplification and manipulation of integrals to facilitate evaluation.
์ถ”์ฒœ ์˜์ƒ:

Substitution Method

The substitution method is a technique used to simplify the evaluation of integrals by changing the variable of integration. By substituting a new variable, often denoted as u, the integral can be transformed into a more manageable form. This method is particularly useful when dealing with composite functions or when the integrand can be expressed in terms of a simpler function.
์ถ”์ฒœ ์˜์ƒ:
07:33
Euler's Method
๊ด€๋ จ ์‹ค์ฒœ
๊ต๊ณผ์„œ ์งˆ๋ฌธ

Left and right Riemann sums Complete the following steps for the given function, interval, and value of n.

f(x) = x + 1 on [0,4]; n = 4

(d) Calculate the left and right Riemann sums.                                                                                                                                                

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๊ต๊ณผ์„œ ์งˆ๋ฌธ

Properties of integrals Consider two functions ฦ’ and g on [1,6] such that โˆซโ‚โถฦ’(๐“) d๐“ = 10 and โˆซโ‚โถg(๐“) d๐“ = 5, โˆซโ‚„โถฦ’(๐“) d๐“ = 5 , and โˆซโ‚โดg(๐“) d๐“ = 2. Evaluate the following integrals.


(d) โˆซโ‚„โถ (g(๐“) โ€• f(๐“) d๐“

80
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๊ต๊ณผ์„œ ์งˆ๋ฌธ

Midpoint Riemann sums Complete the following steps for the given function, interval, and value of n.


ฦ’(๐“) = 2x + 1 on [0,4] ; n = 4


d) Calculate the midpoint Riemann sum.

162
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๊ต๊ณผ์„œ ์งˆ๋ฌธ

Use Table 5.6 to evaluate the following definite integrals.                                                                                                                    

 (d) โˆซโ‚€^ฯ€/ยนโถ sec ยฒ 4๐“ d๐“

80
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๊ต๊ณผ์„œ ์งˆ๋ฌธ

{Use of Tech} Approximating definite integrals Complete the following steps for the given integral and the given value of n. 

(d) Determine which Riemann sum (left or right) underestimates the value of the definite integral and which overestimates the value of the definite integral..


โˆซโ‚€ยฒ (๐“ยฒโ€•2) d๐“ ; n = 4

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๊ต๊ณผ์„œ ์งˆ๋ฌธ

Midpoint Riemann sums Complete the following steps for the given function, interval, and value of n.


ฦ’(๐“) = 1/x on [1,6] ; n = 5


(d) Calculate the midpoint Riemann sum.

235
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