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Ch. 5 - Integration
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243당신이 사용하는 게 아니라요?교과서 변경
5장, 문제 5.3.103

{Use of Tech} Areas of regions Find the area of the region 𝑅 bounded by the graph of ƒ and the 𝓍-axis on the given interval. Graph ƒ and show the region 𝑅.                                              
                                                                                                                                                                                    
 ƒ(𝓍) = 2 ― |𝓍| on [ ― 2 , 4]

검증된 단계별 안내
1
Step 1: Understand the problem. The goal is to find the area of the region R bounded by the graph of ƒ(x) = 2 - |x| and the x-axis over the interval [-2, 4]. This involves integrating the function ƒ(x) over the given interval.
Step 2: Break the function ƒ(x) = 2 - |x| into piecewise components because the absolute value function |x| behaves differently for x < 0 and x ≥ 0. For x < 0, |x| = -x, and for x ≥ 0, |x| = x. Rewrite ƒ(x) as: ƒ(x) = 2 - (-x) = 2 + x for x in [-2, 0], and ƒ(x) = 2 - x for x in [0, 4].
Step 3: Set up the integral to calculate the area. Since the function changes at x = 0, split the integral into two parts: ∫[−2,0](2 + x) dx + ∫[0,4](2 − x) dx.
Step 4: Compute each integral separately. For the first integral ∫[−2,0](2 + x) dx, use the power rule and evaluate the definite integral. For the second integral ∫[0,4](2 − x) dx, similarly apply the power rule and evaluate the definite integral.
Step 5: Add the results of the two integrals to find the total area of the region R. Ensure that any negative values from the integrals are treated as positive since area is always non-negative.

비슷한 문제에 대한 검증된 영상 답변:

이 영상 해법은 위 문제에 도움이 된다고 튜터들이 추천한 것입니다.
영상 길이:
2m

주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Definite Integral

The definite integral of a function over a specified interval represents the net area between the graph of the function and the x-axis. It is calculated using the Fundamental Theorem of Calculus, which connects differentiation and integration. The area can be positive or negative depending on whether the function is above or below the x-axis, and the definite integral provides a precise numerical value for this area.
추천 영상:
가이드 코스
05:43
Definition of the Definite Integral

Graphing Functions

Graphing a function involves plotting its values on a coordinate system, which visually represents the relationship between the input (x-values) and output (f(x)-values). For the function ƒ(x) = 2 - |x|, the graph will show a V-shape, indicating how the function behaves over the interval [-2, 4]. Understanding the graph is crucial for identifying the bounded region and calculating the area accurately.
추천 영상:
가이드 코스
5:53
Graph of Sine and Cosine Function

Area Between Curves

The area between a curve and the x-axis can be found by integrating the function over the specified interval. If the function dips below the x-axis, the area is considered negative, and adjustments may be needed to find the total area. In this case, the area of region R is determined by integrating the function ƒ(x) = 2 - |x| from -2 to 4, ensuring to account for any sections below the x-axis.
추천 영상:
05:23
Finding Area Between Curves on a Given Interval
관련 실천
교과서 질문

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v = [1 / (2t + 1)] (m/s), for 0 ≤ t ≤ 8 ; n = 4

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∫₃⁷ (4𝓍 + 6) d𝓍

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          n                                                                                                                                                                              

    lim   ∑   𝓍*ₖ (ln 𝓍*ₖ) ∆𝓍ₖ on [1,2]                                                                                                                                                                            

  ∆ → 0   k=1                                                                                                                                                                                                                      

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교과서 질문

Definite integrals Use a change of variables or Table 5.6 to evaluate the following definite integrals.                                                                                                                         

                                                                                                                                                                              

 ∫₁³ ( 2ˣ / 2ˣ + 4 ) d𝓍

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교과서 질문

Definite integrals Use a change of variables or Table 5.6 to evaluate the following definite integrals.                                                                                                                         

                                                                                                                                                                              

 ∫π/₄^π/² (cos 𝓍) / (sin² 𝓍) d𝓍

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