Skip to main content
Ch. 2 - Limits and Continuity
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077당신이 사용하는 게 아니라요?교과서 변경
2장, 문제 2.6.15

Limits of Rational Functions


In Exercises 13–22, find the limit of each rational function (a) as x → ∞ and (b) as x → −∞. Write ∞ or −∞ where appropriate.


f(x) = (x + 1)/(x² + 3)

검증된 단계별 안내
1
Step 1: To find the limit of the rational function \( f(x) = \frac{x + 1}{x^2 + 3} \) as \( x \to \infty \), start by analyzing the degrees of the numerator and the denominator. The numerator \( x + 1 \) is of degree 1, and the denominator \( x^2 + 3 \) is of degree 2.
Step 2: Since the degree of the denominator is greater than the degree of the numerator, the limit as \( x \to \infty \) will be determined by the leading terms. Divide each term in the numerator and the denominator by \( x^2 \), the highest power of \( x \) in the denominator.
Step 3: After dividing, the expression becomes \( \frac{\frac{x}{x^2} + \frac{1}{x^2}}{\frac{x^2}{x^2} + \frac{3}{x^2}} = \frac{\frac{1}{x} + \frac{1}{x^2}}{1 + \frac{3}{x^2}} \). As \( x \to \infty \), both \( \frac{1}{x} \) and \( \frac{1}{x^2} \) approach 0.
Step 4: Therefore, the limit of the function as \( x \to \infty \) is \( \frac{0 + 0}{1 + 0} = 0 \).
Step 5: To find the limit as \( x \to -\infty \), repeat the same process. The behavior of the function is similar because the terms \( \frac{1}{x} \) and \( \frac{1}{x^2} \) also approach 0 as \( x \to -\infty \). Thus, the limit is \( \frac{0 + 0}{1 + 0} = 0 \).

비슷한 문제에 대한 검증된 영상 답변:

이 영상 해법은 위 문제에 도움이 된다고 튜터들이 추천한 것입니다.
영상 길이:
3m

주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Limits

Limits are fundamental in calculus, representing the value that a function approaches as the input approaches a certain point. In the context of rational functions, limits help determine the behavior of the function as the variable approaches infinity or negative infinity, which is crucial for understanding end behavior.
추천 영상:
05:50
One-Sided Limits

Rational Functions

Rational functions are expressions formed by the ratio of two polynomials. The behavior of these functions can vary significantly based on the degrees of the numerator and denominator, especially as x approaches infinity or negative infinity, which influences the limits we calculate.
추천 영상:
6:04
Intro to Rational Functions

End Behavior

End behavior refers to the behavior of a function as the input values become very large or very small. For rational functions, this is often determined by the leading terms of the numerator and denominator, which dictate whether the limit approaches a finite value, infinity, or negative infinity.
추천 영상:
03:07
Cases Where Limits Do Not Exist
관련 실천
교과서 질문

Limits as x → ∞ or x → −∞


The process by which we determine limits of rational functions applies equally well to ratios containing noninteger or negative powers of x. Divide numerator and denominator by the highest power of x in the denominator and proceed from there. Find the limits in Exercises 23–36. Write ∞ or −∞ where appropriate.


lim x→∞ (x − 3) / √(4x² + 25)

348
views
교과서 질문

Finding Limits of Differences When x → ±∞


Find the limits in Exercises 84–90. (Hint: Try multiplying and dividing by the conjugate.)


lim x → ∞ (√(x + 9) − √(x + 4))

325
views
교과서 질문

Using the Formal Definition


Prove the limit statements in Exercises 37–50.


limx→1 f(x) = 1 if f(x) = {x², x ≠ 1

2, x = 1

252
views
교과서 질문

Use the Intermediate Value Theorem in Exercises 69–74 to prove that each equation has a solution. Then use a graphing calculator or computer grapher to solve the equations.

x³ − 15x + 1 = 0 (three roots)

338
views
교과서 질문

Finding Limits


In Exercises 3–8, find the limit of each function (a) as x → ∞ and (b) as x → −∞. (You may wish to visualize your answer with a graphing calculator or computer.)


f(x) = 2/x − 3

314
views
교과서 질문

Limits of Average Rates of Change


Because of their connection with secant lines, tangents, and instantaneous rates, limits of the form limh→0 (f(x+h) − f(x)) / h occur frequently in calculus. In Exercises 57–62, evaluate this limit for the given value of x and function f.


f(x) = x², x = 1

333
views