As a result of a heavy rain, the volume of water in a reservoir increased by 1400 acre-ft in 24 hours. Show that at some instant during that period the reservoir’s volume was increasing at a rate in excess of 225,000 gal/min. (An acre-foot is 43,560 ft³, the volume that would cover 1 acre to the depth of 1 ft. A cubic foot holds 7.48 gal.)

검증된 단계별 안내

First, convert the total increase in volume from acre-feet to gallons. Since 1 acre-foot is 43,560 cubic feet and 1 cubic foot holds 7.48 gallons, multiply 1400 acre-feet by 43,560 to get the volume in cubic feet, and then multiply by 7.48 to convert to gallons.

Next, calculate the average rate of increase in gallons per minute over the 24-hour period. There are 24 hours in a day and 60 minutes in an hour, so multiply 24 by 60 to find the total number of minutes in the period.

Divide the total increase in gallons by the total number of minutes to find the average rate of increase in gallons per minute.

Apply the Mean Value Theorem for derivatives, which states that if a function is continuous on a closed interval and differentiable on the open interval, then there exists at least one point in the interval where the instantaneous rate of change (derivative) equals the average rate of change over the interval.

Since the average rate of increase is less than 225,000 gal/min, and the total increase is 1400 acre-ft, use the Mean Value Theorem to conclude that there must be at least one instant during the 24-hour period where the rate of increase exceeded 225,000 gal/min.

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주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Rate of Change

In calculus, the rate of change refers to how a quantity changes over time. It is often represented as a derivative, which measures the instantaneous rate of change of a function. In this context, we are interested in how the volume of water in the reservoir changes with respect to time, specifically looking for the maximum rate of increase during the 24-hour period.

Mean Value Theorem

The Mean Value Theorem states that if a function is continuous on a closed interval and differentiable on the open interval, there exists at least one point where the instantaneous rate of change (derivative) equals the average rate of change over that interval. This theorem is crucial for this problem as it allows us to conclude that there must be a moment when the volume increase exceeds the average rate calculated over the 24 hours.

Unit Conversion

Unit conversion is the process of converting a quantity expressed in one set of units to another. In this problem, we need to convert the increase in volume from acre-feet to gallons per minute to compare it with the required rate. Understanding how to convert between these units is essential for accurately determining whether the instantaneous rate exceeds 225,000 gallons per minute.