2. When applying the formula for integration by parts, how do you choose the u and dv? How can you apply integration by parts to an integral of the form ∫ f(x) dx?
Ch. 8 - Techniques of Integration
8장, 문제 8.AAE.11
Finding arc length
Find the length of the curve
y = ∫ from 0 to x of √(cos(2t)) dt, 0 ≤ x ≤ π/4.
검증된 단계별 안내1
Recognize that the curve is defined by an integral function: \(y = \int_0^x \sqrt{\cos(2t)} \, dt\). To find the arc length of \(y\) from \(x=0\) to \(x=\frac{\pi}{4}\), we use the arc length formula for a function \(y=f(x)\): \(L = \int_a^b \sqrt{1 + \left(\frac{dy}{dx}\right)^2} \, dx\).
Find the derivative \(\frac{dy}{dx}\) using the Fundamental Theorem of Calculus. Since \(y\) is defined as an integral with variable upper limit \(x\), we have \(\frac{dy}{dx} = \sqrt{\cos(2x)}\).
Substitute \(\frac{dy}{dx}\) into the arc length formula: \(L = \int_0^{\frac{\pi}{4}} \sqrt{1 + \left(\sqrt{\cos(2x)}\right)^2} \, dx\).
Simplify the expression inside the square root: \(\left(\sqrt{\cos(2x)}\right)^2 = \cos(2x)\), so the integrand becomes \(\sqrt{1 + \cos(2x)}\).
Use a trigonometric identity to simplify \(1 + \cos(2x)\). Recall that \(1 + \cos(2x) = 2 \cos^2(x)\). Therefore, the integrand simplifies to \(\sqrt{2 \cos^2(x)} = \sqrt{2} |\cos(x)|\). Since \(x\) is in \([0, \frac{\pi}{4}]\) where \(\cos(x)\) is positive, the absolute value can be removed. The arc length integral becomes \(L = \int_0^{\frac{\pi}{4}} \sqrt{2} \cos(x) \, dx\).

비슷한 문제에 대한 검증된 영상 답변:
이 영상 해법은 위 문제에 도움이 된다고 튜터들이 추천한 것입니다.
영상 길이:
4m주요 개념
질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.
Arc Length Formula for Parametric and Integral-Defined Curves
The arc length of a curve y = f(x) from a to b is given by the integral of the square root of 1 plus the derivative squared, ∫_a^b √(1 + (dy/dx)^2) dx. When y is defined as an integral function, this formula still applies by first finding dy/dx.
추천 영상:
가이드 코스
Arc Length of Parametric Curves
Fundamental Theorem of Calculus
This theorem connects differentiation and integration, stating that if y = ∫_0^x g(t) dt, then dy/dx = g(x). It allows us to find the derivative of an integral-defined function, which is essential for computing the arc length.
추천 영상:
가이드 코스
Fundamental Theorem of Calculus Part 1
Handling Square Roots of Trigonometric Functions
The integrand involves √(cos(2t)), which requires understanding the domain where cos(2t) is non-negative to ensure the square root is real. Recognizing trigonometric identities and domain restrictions helps in evaluating or simplifying the integral.
추천 영상:
가이드 코스
Introduction to Trigonometric Functions
관련 실천
교과서 질문
23
views
교과서 질문
18. Finding volume (Continuation of Exercise 17.) Find the volume of the solid generated by revolving the region R about:
a. the y-axis.
38
views
교과서 질문
Evaluate the integrals in Exercises 1–6.
∫ dt / (t - √(1 - t²))
30
views
교과서 질문
7. What is the goal of the method of partial fractions?
4
views
교과서 질문
Evaluate the integrals in Exercises 69–134. The integrals are listed in random order so you need to decide which integration technique to use.
∫ dy / (y² − 2y + 2)
17
views
교과서 질문
Use the substitutions in Equations (1)–(4) to evaluate the integrals in Exercises 33–40. Integrals like these arise in calculating the average angular velocity of the output shaft of a universal joint when the input and output shafts are not aligned.
∫(from π/2 to 2π/3) cos θ dθ / (sin θ cos θ + sin θ)
36
views
