Skip to main content
Ch. 2 - Functions and Graphs
Blitzer - College Algebra 8th Edition
Blitzer8th EditionCollege AlgebraISBN: 9780136970514당신이 사용하는 게 아니라요?교과서 변경
3장, 문제 69

Find a. (fog) (x) b. the domain of f o g. f(x) = x/(x+1), g(x) = 4/x

검증된 단계별 안내
1
First, recall that the composition of functions (fog)(x) means f(g(x)). So, we need to substitute g(x) into the function f.
Given f(x) = \(\frac{x}{x+1}\) and g(x) = \(\frac{4}{x}\), substitute g(x) into f(x) to get (fog)(x) = f\(\left\)(\(\frac{4}{x}\)\(\right\)) = \(\frac{\frac{4}{x}\)}{\(\frac{4}{x}\) + 1}.
Simplify the expression for (fog)(x) by combining the terms in the denominator: \(\frac{4}{x}\) + 1 = \(\frac{4}{x}\) + \(\frac{x}{x}\) = \(\frac{4 + x}{x}\). Then rewrite (fog)(x) as \(\frac{\frac{4}{x}\)}{\(\frac{4 + x}{x}\)}.
To simplify the complex fraction, multiply numerator and denominator by x to eliminate the denominators inside the fraction: (fog)(x) = \(\frac{4}{4 + x}\).
For the domain of (fog), consider the domain restrictions from both f and g. First, g(x) = \(\frac{4}{x}\) requires x \(\neq\) 0. Next, f(g(x)) requires the denominator of f(g(x)) to be nonzero, so 4 + x \(\neq\) 0, which means x \(\neq\) -4. Therefore, the domain of (fog) is all real numbers except x = 0 and x = -4.

비슷한 문제에 대한 검증된 영상 답변:

이 영상 해법은 위 문제에 도움이 된다고 튜터들이 추천한 것입니다.
영상 길이:
3m

주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Function Composition

Function composition involves applying one function to the result of another, denoted as (f ∘ g)(x) = f(g(x)). It requires substituting the entire expression of g(x) into f(x), which helps in combining two functions into a single expression.
추천 영상:
가이드 코스
4:56
Function Composition

Domain of a Function

The domain of a function is the set of all input values (x) for which the function is defined. When composing functions, the domain of (f ∘ g) includes all x-values in the domain of g such that g(x) is in the domain of f.
추천 영상:
가이드 코스
3:51
Domain Restrictions of Composed Functions

Restrictions from Denominators

Functions with variables in denominators have restrictions where the denominator cannot be zero. Identifying these values is crucial to determine the domain, especially when composing functions, to avoid division by zero.
추천 영상:
가이드 코스
02:58
Rationalizing Denominators