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Ch. 2 - Acids and Bases: Central to Understanding Organic Chemistry
Bruice - Organic Chemistry 8th Edition
Bruice8th EditionOrganic ChemistryISBN: 9780135213711당신이 사용하는 게 아니라요?교과서 변경
모든 교과서Bruice 8th EditionCh. 2 - Acids and Bases: Central to Understanding Organic Chemistry문제 61a
2장, 문제 61a

Give the products of the following acid–base reactions and indicate whether reactants or products are favored at equilibrium.
a. Chemical equation showing an acid-base reaction with reactants and products, indicating equilibrium direction.

검증된 단계별 안내
1
Identify the acid and base on both sides of the reaction. The acid is the species that donates a proton (H⁺), and the base is the species that accepts a proton.
Determine the conjugate acid and conjugate base formed after the proton transfer. The acid loses a proton to form its conjugate base, and the base gains a proton to form its conjugate acid.
Use the pKa values provided in Section 2.3 to compare the acidity of the acid on the reactant side and the conjugate acid on the product side. Recall that a lower pKa value indicates a stronger acid.
Determine the direction of equilibrium by comparing the strengths of the acids. Equilibrium favors the side with the weaker acid (higher pKa value).
Write the products of the reaction, clearly indicating the conjugate acid and conjugate base, and state whether the equilibrium favors the reactants or products based on the pKa comparison.

비슷한 문제에 대한 검증된 영상 답변:

이 영상 해법은 위 문제에 도움이 된다고 튜터들이 추천한 것입니다.
영상 길이:
3m

주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Acid-Base Reactions

Acid-base reactions involve the transfer of protons (H+) between reactants. An acid donates a proton, while a base accepts it. Understanding the nature of the acids and bases involved is crucial for predicting the products of the reaction and determining the direction of equilibrium.
추천 영상:
02:49
The Lewis definition of acids and bases.

pKa and Equilibrium

The pKa value is a measure of the strength of an acid; lower pKa values indicate stronger acids. In acid-base reactions, the equilibrium position can be predicted by comparing the pKa values of the acids and their conjugate bases. The reaction favors the side with the weaker acid (higher pKa) at equilibrium.
추천 영상:
02:19
The relationship between equilibrium constant and pKa.

Equilibrium Position

The equilibrium position of a reaction indicates the relative concentrations of reactants and products at equilibrium. In acid-base reactions, the favored side is determined by the stability of the resulting species, which is influenced by factors such as electronegativity and resonance. Understanding these concepts helps in predicting the outcome of the reaction.
추천 영상:
가이드 코스
2:49
Reactions at the Allylic Position Concept 5
관련 실천
교과서 질문

Rank the following alcohols from strongest to weakest acid.

CH2═CHCH2OH; CH3CH2CH2OH; HC≡CCH2OH

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교과서 질문

Explain the relative acidities.

CH2═CHCH2OH, CH3CH2CH2OH, HC≡CCH2OH

1624
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교과서 질문

Give the products of the following acid–base reactions and indicate whether reactants or products are favored at equilibrium.

b. CH3CH2OH + -NH2 ⇌

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교과서 질문

For each of the following compounds, draw the form that predominates at pH = 3, pH = 6, pH = 10, and pH = 14:

c. CF3CH2OH (pKa = 12.4)

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교과서 질문

For each of the following compounds, draw the form that predominates at pH = 3, pH = 6, pH = 10, and pH = 14:

a. CH3COOH (pKa = 4.8)

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교과서 질문

For each of the following compounds, draw the form that predominates at pH = 3, pH = 6, pH = 10, and pH = 14:

b. CH3CH2N+H3 (pKa = 11.0)

1222
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