Explain why only a substitution product and no elimination product is obtained when the following compound reacts with sodium methoxide:

검증된 단계별 안내

Step 1: Analyze the structure of the compound. The molecule is a cyclohexane ring with two ethyl groups attached in a trans configuration and an iodine atom attached in an axial position. Sodium methoxide (CH3ONa) is a strong nucleophile and base.

Step 2: Consider the reaction mechanism. Sodium methoxide can act as a nucleophile in a substitution reaction or as a base in an elimination reaction. The axial iodine atom is a good leaving group, making the molecule prone to nucleophilic substitution.

Step 3: Evaluate steric hindrance for elimination. For elimination to occur, a β-hydrogen must be anti-periplanar to the leaving group (iodine). In this case, the β-hydrogens on the cyclohexane ring are equatorial, and none are anti-periplanar to the axial iodine. This geometric constraint prevents elimination.

Step 4: Favor substitution. Since elimination is sterically hindered, substitution becomes the favored pathway. Sodium methoxide attacks the carbon bonded to iodine, replacing the iodine with a methoxy group (CH3O−). This reaction proceeds via an SN2 mechanism due to the strong nucleophile and the primary nature of the carbon attached to iodine.

Step 5: Conclude why elimination does not occur. The lack of anti-periplanar β-hydrogens and the favorable conditions for SN2 substitution explain why only the substitution product is obtained in this reaction.

비슷한 문제에 대한 검증된 영상 답변:

이 영상 해법은 위 문제에 도움이 된다고 튜터들이 추천한 것입니다.

영상 길이:

주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Nucleophilic Substitution Reactions

Nucleophilic substitution reactions involve the replacement of a leaving group in a molecule by a nucleophile. In this case, sodium methoxide (CH3ONa) acts as a nucleophile, attacking the carbon atom bonded to the iodine (the leaving group). The reaction typically follows either an SN1 or SN2 mechanism, depending on the structure of the substrate and the conditions.

Elimination Reactions

Elimination reactions involve the removal of a small molecule (like water or hydrogen halide) from a larger molecule, resulting in the formation of a double bond. The E2 mechanism is a common type of elimination that requires a strong base and typically occurs in a concerted manner. However, in this scenario, the steric hindrance and the structure of the substrate favor substitution over elimination.

Steric Hindrance

Steric hindrance refers to the prevention of reactions due to the spatial arrangement of atoms within a molecule. In this case, the bulky substituents on the cyclohexane ring create significant steric hindrance, making it difficult for the base to access the hydrogen atoms necessary for elimination. This steric effect favors the nucleophilic substitution pathway, leading to the formation of a substitution product instead of an elimination product.

Explain why only a substitution product and no elimination product is obtained when the following ­compound reacts with sodium methoxide: