In the following reactions,
(iv) provide an arrow-pushing mechanism of the proton transfer that will occur, and
(v) predict the product of the reactions. [You'll need to provide the lone pairs here.]
(a)

검증된 단계별 안내

Step 1: Analyze the reactants. The molecule on the left is a cyanide ion (N≡C⁻), which has a negative charge on the carbon atom. The molecule on the right is hydrochloric acid (HCl), a strong acid that can donate a proton (H⁺).

Step 2: Identify the nucleophile and electrophile. The cyanide ion acts as the nucleophile because the negatively charged carbon has lone pairs of electrons that can attack an electrophile. HCl acts as the electrophile because the hydrogen atom is partially positive and can accept electrons.

Step 3: Draw the arrow-pushing mechanism. The lone pair of electrons on the carbon atom of the cyanide ion will attack the hydrogen atom of HCl, forming a bond between the carbon and hydrogen. Simultaneously, the bond between hydrogen and chlorine will break, transferring the electrons to chlorine and forming a chloride ion (Cl⁻).

Step 4: Represent the lone pairs. After the proton transfer, the cyanide ion becomes neutral, forming hydrogen cyanide (HC≡N). The chloride ion (Cl⁻) will have three lone pairs of electrons.

Step 5: Predict the product. The final product of the reaction is hydrogen cyanide (HC≡N) and a chloride ion (Cl⁻). Ensure that all lone pairs are correctly represented in the product structure.

비슷한 문제에 대한 검증된 영상 답변:

이 영상 해법은 위 문제에 도움이 된다고 튜터들이 추천한 것입니다.

영상 길이:

주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Proton Transfer Mechanism

Proton transfer mechanisms involve the movement of a proton (H+) from one molecule to another, typically facilitated by the presence of a base or an acid. In this context, the nucleophile (the species with a lone pair) will attack the proton of HCl, leading to the formation of a new bond. Understanding this mechanism is crucial for predicting the products of acid-base reactions.

Nucleophiles and Electrophiles

Nucleophiles are species that donate an electron pair to form a chemical bond, while electrophiles are electron-deficient species that accept electron pairs. In the given reaction, the nucleophile is the cyanide ion (C≡N-), which will attack the electrophilic hydrogen in HCl. Recognizing the roles of nucleophiles and electrophiles is essential for predicting reaction outcomes.

Lone Pairs and Bond Formation

Lone pairs are pairs of valence electrons that are not involved in bonding and can participate in chemical reactions. In the context of the reaction, the lone pair on the cyanide ion is crucial for the proton transfer, as it allows the nucleophile to bond with the proton from HCl. Identifying and utilizing lone pairs is key to understanding reaction mechanisms in organic chemistry.

In the following reactions, (iv) provide an arrow-pushing mechanism of the proton transfer that will occur, and (v) predict the product of the reactions. [You'll need to provide the lone pairs here.](a)