교과서 질문
Predict the hybridization and geometry of the carbon and nitrogen atoms in the following molecules and ions. (Hint: Resonance.)
d.
1052
views
Ch.1 - Structure and Bonding
Wade9th EditionOrganic ChemistryISBN: 9780135213728
당신이 사용하는 게 아니라요?교과서 변경다른 교과서를 선택하세요
TOC.tableOfContents
- Ch.1 - Structure and Bonding107
- Ch. 2 - Acids and Bases; Functional Groups115
- Ch.3 - Structure and Stereochemistry of Alkanes100
- Ch.4 - The Study of Chemical Reactions99
- Ch.5 - Stereochemistry93
- Ch.6 - Alkyl Halides; Nucleophilic Substitution118
- Ch. 7 - Structure and Synthesis of Alkenes; Elimination158
- Ch.8 - Reactions of Alkenes171
- Ch.9 - Alkynes91
- Ch.10 - Structure and Synthesis of Alcohols143
- Ch.11 - Reactions of Alcohols104
- Ch. 12 - Infrared Spectroscopy and Mass Spectrometry22
- Ch. 13 - Nuclear Magnetic Resonance Spectroscopy45
- Ch. 14 - Ethers, Epoxides, and Thioethers72
- Ch. 15 - Conjugated Systems, Orbital Symmetry, and Ultraviolet Spectroscopy89
- Ch. 16 - Aromatic Compounds74
- Ch. 17 - Reactions of Aromatic Compounds126
- Ch. 18 - Ketones and Aldehydes193
- Ch. 19 - Amines129
- Ch. 20 - Carboxylic Acids77
- Ch. 21 - Carboxylic Acid Derivatives141
- Ch. 22 - Condensations and Alpha Substitutions of Carbonyl Compounds175
- Ch. 23 - Carbohydrates and Nucleic Acids93
- Ch. 24 - Amino Acids, Peptides, and Proteins54
1장, 문제 54a,b,c
Predict the hybridization and geometry of the carbon and nitrogen atoms in the following molecules and ions. (Hint: Resonance.)
a. 
b. 
c. 
검증된 단계별 안내1
For molecule (a) [CH3C(=O)CH2]-, identify the hybridization of each carbon atom. The first carbon (CH3) is sp3 hybridized due to its four single bonds. The second carbon (C=O) is sp2 hybridized because it forms a double bond with oxygen and a single bond with the adjacent carbon. The third carbon (CH2-) is sp3 hybridized as it has three single bonds and a lone pair, considering the negative charge.
For molecule (a), determine the geometry around each carbon atom. The first carbon (CH3) has a tetrahedral geometry due to its sp3 hybridization. The second carbon (C=O) has a trigonal planar geometry because of its sp2 hybridization. The third carbon (CH2-) also has a tetrahedral geometry due to its sp3 hybridization.
For molecule (b) [H2NCH=CHCH2]+, identify the hybridization of the nitrogen and carbon atoms. The nitrogen atom is sp3 hybridized as it forms three sigma bonds and has a lone pair. The first carbon (CH) is sp2 hybridized due to its double bond with the second carbon. The second carbon (CH) is also sp2 hybridized because of its double bond with the first carbon and a single bond with the third carbon. The third carbon (CH2)+ is sp2 hybridized due to the positive charge and its bonding.
For molecule (b), determine the geometry around each atom. The nitrogen atom has a trigonal pyramidal geometry due to its sp3 hybridization. The first and second carbons (CH=CH) have a trigonal planar geometry because of their sp2 hybridization. The third carbon (CH2)+ also has a trigonal planar geometry due to its sp2 hybridization.
For molecule (c) [CH2C≡N]-, identify the hybridization of the carbon and nitrogen atoms. The first carbon (CH2) is sp3 hybridized as it forms three sigma bonds and has a lone pair. The second carbon (C≡N) is sp hybridized due to its triple bond with nitrogen. The nitrogen atom is also sp hybridized because of its triple bond with carbon.
비슷한 문제에 대한 검증된 영상 답변:
이 영상 해법은 위 문제에 도움이 된다고 튜터들이 추천한 것입니다.
영상 길이:
8m주요 개념
질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.
Hybridization
Hybridization is the concept of mixing atomic orbitals to form new hybrid orbitals that can accommodate the bonding requirements of atoms in a molecule. For carbon, common hybridizations include sp3, sp2, and sp, which correspond to different geometries: tetrahedral, trigonal planar, and linear, respectively. Understanding hybridization helps predict the shape and bond angles in molecules.
추천 영상:
10:43
Using bond sites to predict hybridization
Molecular Geometry
Molecular geometry refers to the three-dimensional arrangement of atoms within a molecule. It is determined by the number of bonding pairs and lone pairs of electrons around the central atom, which influences the overall shape. Common geometries include linear, trigonal planar, tetrahedral, and trigonal bipyramidal, each with specific bond angles that can be predicted based on hybridization.
추천 영상:
07:44Molecular Geometry Explained.
Resonance
Resonance is a phenomenon in which a molecule can be represented by two or more valid Lewis structures, known as resonance structures. These structures differ only in the placement of electrons, not in the arrangement of atoms. Resonance helps explain the delocalization of electrons in molecules, affecting their stability, reactivity, and hybridization, which is crucial for accurately predicting molecular geometry.
추천 영상:
03:04Drawing Resonance Structures
관련 실천
교과서 질문
For each of the following compounds and ions,
1. Draw a Lewis structure.
2. Show the kinds of orbitals that overlap to form each bond.
3. Give approximate bond angles around each atom except hydrogen
h.
655
views
교과서 질문
For each of the following compounds and ions,
1. Draw a Lewis structure.
2. Show the kinds of orbitals that overlap to form each bond.
3. Give approximate bond angles around each atom except hydrogen.
g.
918
views
교과서 질문
Predict the hybridization and geometry of the carbon and nitrogen atoms in the following molecules and ions. (Hint: Resonance.)
f.
939
views
교과서 질문
In most amines, the nitrogen atom is sp3 hybridized, with a pyramidal structure and bond angles close to 109°. In urea, both nitrogen atoms are found to be planar, with bond angles close to 120°. Explain this surprising finding. (Hint: Consider resonance forms and the overlap needed in them.)
2722
views
교과서 질문
Predict the hybridization and geometry of the carbon and nitrogen atoms in the following molecules and ions. (Hint: Resonance.)
e.
877
views