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Ch. 2 - Acids and Bases; Functional Groups
Wade - Organic Chemistry 9th Edition
Wade9th EditionOrganic ChemistryISBN: 9780135213728당신이 사용하는 게 아니라요?교과서 변경
모든 교과서Wade 9th EditionCh. 2 - Acids and Bases; Functional Groups문제 42g
2장, 문제 42g

Predict the products of the following acid–base reactions.
(g) HCOOH + CH3O– ⇌

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1
Identify the acid and the base in the reaction. In this case, HCOOH (formic acid) is the acid, and CH3O- (methoxide ion) is the base.
Determine the conjugate base of the acid. The conjugate base of HCOOH is HCOO- (formate ion), which is formed by the loss of a proton (H+).
Determine the conjugate acid of the base. The conjugate acid of CH3O- is CH3OH (methanol), which is formed by the gain of a proton (H+).
Write the products of the reaction using the conjugate acid and base identified. The products are HCOO- and CH3OH.
Verify the reaction by checking the direction of equilibrium. Since methanol is a weaker acid than formic acid, the equilibrium will favor the formation of the weaker acid and base, confirming the products as HCOO- and CH3OH.

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주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Acid-Base Reactions

Acid-base reactions involve the transfer of protons (H+) between reactants. In this context, HCOOH (formic acid) acts as an acid, donating a proton, while CH3O- (methoxide ion) acts as a base, accepting a proton. Understanding the roles of acids and bases is crucial for predicting the products of such reactions.
추천 영상:
02:49
The Lewis definition of acids and bases.

Conjugate Acid-Base Pairs

In an acid-base reaction, the acid and base transform into their respective conjugate base and conjugate acid. For HCOOH, the conjugate base is HCOO- (formate ion), and for CH3O-, the conjugate acid is CH3OH (methanol). Recognizing these pairs helps in identifying the products formed after the proton transfer.
추천 영상:
가이드 코스
2:56
Base Pairing Concept 1

Equilibrium in Acid-Base Reactions

Acid-base reactions often reach an equilibrium state, where the forward and reverse reactions occur at the same rate. The position of equilibrium depends on the relative strengths of the acids and bases involved. In this reaction, the equilibrium will favor the side with the weaker acid and base, which can be determined by comparing pKa values.
추천 영상:
04:00
Determining Acid/Base Equilibrium
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