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Ch.6 - Alkyl Halides; Nucleophilic Substitution
Wade - Organic Chemistry 9th Edition
Wade9th EditionOrganic ChemistryISBN: 9780135213728당신이 사용하는 게 아니라요?교과서 변경
6장, 문제 57b

Propose mechanisms to account for the observed products in the following reactions.
(b) Chemical reaction diagram showing allylic bromination with NBS and light, yielding products with bromine.

검증된 단계별 안내
1
Step 1: Recognize that the reaction involves allylic bromination using NBS (N-Bromosuccinimide) under light (hv). NBS is commonly used to selectively brominate allylic or benzylic positions in the presence of a double bond.
Step 2: Initiation phase: Light (hv) causes homolytic cleavage of the N-Br bond in NBS, generating a bromine radical (Br•). This radical is highly reactive and initiates the reaction.
Step 3: Propagation phase: The bromine radical abstracts a hydrogen atom from the allylic position of the cyclohexene molecule, forming an allylic radical. The allylic radical is stabilized by resonance, creating two possible resonance structures.
Step 4: Bromine from NBS reacts with the allylic radical to form the brominated products. The resonance structures of the allylic radical lead to two different products: (1) 3-bromocyclohexene and (2) 1-bromocyclohexene.
Step 5: Termination phase: Any remaining radicals combine to form stable molecules, completing the reaction. The observed products are the result of the selective bromination at the allylic positions due to the resonance stabilization of the intermediate radical.

비슷한 문제에 대한 검증된 영상 답변:

이 영상 해법은 위 문제에 도움이 된다고 튜터들이 추천한 것입니다.
영상 길이:
5m

주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Allylic Bromination

Allylic bromination is a reaction where bromine is added to the allylic position of an alkene or alkane. This process typically involves the formation of a radical intermediate, allowing for the substitution of a hydrogen atom with a bromine atom. The reaction is often facilitated by reagents like N-bromosuccinimide (NBS) in the presence of light, which generates bromine radicals that can abstract hydrogen atoms from the allylic position.
추천 영상:
00:54
Mechanism of Allylic Bromination.

Radical Mechanism

The radical mechanism involves the formation and reaction of free radicals, which are highly reactive species with unpaired electrons. In the context of allylic bromination, the mechanism proceeds through three main steps: initiation (formation of bromine radicals), propagation (reaction of radicals with the substrate), and termination (recombination of radicals). Understanding this mechanism is crucial for predicting the products of the reaction and the regioselectivity of bromination.
추천 영상:
03:28
The mechanism of Radical Polymerization.

Regioselectivity

Regioselectivity refers to the preference of a chemical reaction to yield one structural isomer over others when multiple possibilities exist. In allylic bromination, the regioselectivity is influenced by the stability of the radical intermediates formed during the reaction. More stable radicals, such as those formed at more substituted carbon centers, are favored, leading to specific products. This concept is essential for predicting the distribution of products in the reaction.
추천 영상:
05:09
Heck Reaction
관련 실천
교과서 질문

Show the products you expect when each compound reacts with NBS with light shining on the reaction.

(c)

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교과서 질문

Show the products you expect when each compound reacts with NBS with light shining on the reaction.

(a)

(b)

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교과서 질문

The following reaction takes place under second-order conditions (strong nucleophile), yet the structure of the product shows rearrangement. Also, the rate of this reaction is several thousand times faster than the rate of substitution of ­hydroxide ion on 2-chlorobutane under similar conditions. Propose a mechanism to explain the enhanced rate and ­rearrangement observed in this unusual reaction. (“Et” is the abbreviation for ethyl.)

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교과서 질문

Propose mechanisms to account for the observed products in the following reactions.

(a)

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교과서 질문

A student adds NBS to a solution of 1-methylcyclohexene and irradiates the mixture with a sunlamp until all the NBS has reacted. After a careful distillation, the product mixture contains two major products of formula C7H11Br.

(a) Draw the resonance forms of the three possible allylic free radical intermediates.

(b) Rank these three intermediates from most stable to least stable.

(c) Draw the products obtained from each free-radical intermediate.

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교과서 질문

Furfuryl chloride can undergo substitution by both SN2 and SN1 mechanisms. Because it is a 1° alkyl halide, we expect SN2 but not SN1 reactions. Draw a mechanism for the SN1 reaction shown below, paying careful attention to the structure of the intermediate. How can this primary halide undergo SN1 reactions?

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