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Ch. 36 - The Special Theory of Relativity
Giancoli Douglas - Physics for Scientists and Engineers 5th edition
Giancoli Douglas5th editionPhysics for Scientists and EngineersISBN: 9780137488179당신이 사용하는 게 아니라요?교과서 변경
35장, 문제 58

Show that the kinetic energy K of a particle of mass m is related to its momentum p by the equation p=K2+2Kmc2cp=\(\frac{\sqrt{K^2+2Kmc^2}\)}{c}.

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1
Start with the definition of kinetic energy (K) for a particle: \( K = \frac{1}{2}mv^2 \), where \( m \) is the mass of the particle and \( v \) is its velocity.
Recall the definition of momentum (p): \( p = mv \). Substitute \( v \) from the momentum equation into the kinetic energy equation.
Rearrange the kinetic energy equation to express \( v \) in terms of \( p \): \( v = \frac{p}{m} \). Substitute this expression for \( v \) into \( K = \frac{1}{2}mv^2 \).
Simplify the equation: \( K = \frac{1}{2}m\left(\frac{p}{m}\right)^2 \), which becomes \( K = \frac{p^2}{2m} \).
Rearrange the equation \( K = \frac{p^2}{2m} \) to solve for \( p \): \( p = \sqrt{2Km} \). This shows the relationship between kinetic energy and momentum.

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이 영상 해법은 위 문제에 도움이 된다고 튜터들이 추천한 것입니다.
영상 길이:
4m

주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Kinetic Energy

Kinetic energy (K) is the energy that a particle possesses due to its motion. It is defined mathematically as K = (1/2)mv², where m is the mass and v is the velocity of the particle. This concept is fundamental in understanding how energy is converted and transferred in physical systems.
추천 영상:
가이드 코스
06:07
Intro to Rotational Kinetic Energy

Momentum

Momentum (p) is a vector quantity defined as the product of an object's mass and its velocity, expressed as p = mv. It is a key concept in physics because it is conserved in isolated systems, meaning the total momentum before and after an event remains constant. Understanding momentum is crucial for analyzing collisions and interactions between particles.
추천 영상:
가이드 코스
05:17
Intro to Momentum

Relativistic Effects

Relativistic effects become significant at speeds approaching the speed of light, affecting the relationship between kinetic energy and momentum. In relativistic physics, the equations for kinetic energy and momentum are modified to account for the increase in mass and energy as an object's speed increases. This understanding is essential for deriving the relationship between kinetic energy and momentum in high-energy physics scenarios.
추천 영상:
가이드 코스
07:40
The Doppler Effect
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Suppose a spacecraft of mass 17,000 kg was accelerated to 0.22c.

(a) How much kinetic energy would it have?

(b) If you used the classical formula for kinetic energy, by what percentage would you be in error?

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(III) If a particle moves in the xy plane of system S (Fig. 36–12) with speed u in a direction that makes an angle θ with the x axis, show that it makes an angle θ' in S' given by tanθ′=(sinθ)1−v2/c2/(cosθ−v/u)\(\tan\)\(\theta\)^{\(\prime\)}=(\(\sin\[\theta\))\(\sqrt{1-v^2/c^2}\)/(\(\cos\]\theta\)-v/u).

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(III) (a) In reference frame S, a particle has momentum p→=pxi\(\overrightarrow{\mathbf{p}\)}=p_{x}\(\mathbf{i}\) along the positive x axis. Show that in frame S’, which moves with speed v as in Fig. 36–12, the momentum has components

px′=px−vE/c21−v2/c2p_{x}^{\(\prime\)}=\(\frac{px-vE/c^2}{\sqrt{1-v^2/c^2}\)}

py′=pyp_{y}^{\(\prime\)}=py

pz′=pzp_{z}^{\(\prime\)}=pz

E′=E−pxv1−v2/c2.E^{\(\prime\)}=\(\frac{E-p_{x}\)v}{\(\sqrt{1-v^2/c^2}\)}.

(These transformation equations hold, actually, for any direction of p→\(\overrightarrow{\mathbf{p}\)}, as long as the motion of S' is along the x axis.) (b) Show that px, py, pz, E/c transform according to the Lorentz transformation in the same way as x, y, z, ct.

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Make a graph of the kinetic energy versus momentum for (a) a particle of nonzero mass, and (b) a particle with zero mass.

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A spaceship moving toward Earth at 0.65c transmits radio signals at 95.0 MHz. At what frequency should Earth receivers be tuned?

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