Solve the given quadratic equation by completing the square.
$x^2+3x-5=0$

$x=-\(\frac\)32,x=\(\frac\)52$

$x=-\(\frac\)32,x=\(\sqrt{29}\)$

$x=\(\frac{-3+\sqrt{29}\)}{2},x=\(\frac{-3-\sqrt{29}\)}{2}$

$x=\(\frac{3+\sqrt{29}\)}{2},x=\(\frac{3-\sqrt{29}\)}{2}$