after-the-first-equivalence-point-50-ml-of-0050-m-koh-is-added-to-100-ml-of-0100

Question

After the first equivalence point, 50 mL of 0.050 M KOH is added to 100 mL of 0.100 M diprotic acid. Calculate the pH considering the removal of the second acidic hydrogen. Assume K_{a2} = 6.4 x $$10^{-8}.$$

Accepted Answer

6.72

Answer

8.00

Answer

5.00

Answer

7.00

After the first equivalence point, 50 mL of 0.050 M KOH is added to 100 mL of 0.100 M diprotic acid. Calculate the pH considering the removal of the second acidic hydrogen. Assume Ka2 = 6.4 x 10-8.

After the first equivalence point, 50 mL of 0.050 M KOH is added to 100 mL of 0.100 M diprotic acid. Calculate the pH considering the removal of the second acidic hydrogen. Assume K_a2 = 6.4 x 10^-8.