Find the vertex using the vertex formula \(x = -\frac{b}{2a}\), where \(a = 4\) and \(b = -8\). Calculate \(x\) coordinate of the vertex.
Substitute the \(x\) value of the vertex back into the equation to find the \(y\) coordinate of the vertex.
Find the \(y\)-intercept by evaluating the function at \(x = 0\), which gives the point \((0, y)\).
Find the \(x\)-intercepts by solving the quadratic equation \(4x^2 - 8x + 5 = 0\) using the quadratic formula \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\).