Beginning & Intermediate Algebra
Which explanation correctly demonstrates why (a+b)2≠a2+b2(a + b)^2 \(\neq\) a^2 + b^2?
Compute (3x+2)2(3x + 2)^2.
Factor x2+12x+36x^2 + 12x + 36 completely into a squared binomial.
Simplify (2x+3)2−(2x−3)2(2x + 3)^2 - (2x - 3)^2 by applying the Difference of Squares identity.
Expand (12x+3)2\(\left\)({\(\displaystyle\]\frac{1}{2}\)x+3}\(\right\))^2.
