Is the constant function a solution to the differential equation ?
A
No, because the derivative is not zero when .
B
No, because does not satisfy the initial condition .
C
Yes, because any constant function is a solution to this differential equation.
D
Yes, because substituting into the equation makes both sides equal.
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검증된 단계별 안내
1
Step 1: Understand the problem. We are tasked with verifying whether the constant function y(t) = -4 is a solution to the differential equation y' = t^2(y + 4). To do this, we need to substitute y(t) = -4 into the equation and check if both sides are equal.
Step 2: Compute the derivative of y(t). Since y(t) = -4 is a constant function, its derivative y' is 0. This is because the derivative of a constant is always zero.
Step 3: Substitute y(t) = -4 and y' = 0 into the differential equation y' = t^2(y + 4). Replace y' with 0 and y with -4 in the equation.
Step 4: Simplify the right-hand side of the equation. Substitute y = -4 into the expression t^2(y + 4). This becomes t^2((-4) + 4), which simplifies to t^2(0) = 0.
Step 5: Compare both sides of the equation. The left-hand side is y' = 0, and the right-hand side is t^2(y + 4) = 0. Since both sides are equal, y(t) = -4 satisfies the differential equation.