Step 1: Recall the formula for the length of a curve in parametric form. The length of a curve r(t) = (x(t), y(t), z(t)) from t = a to t = b is given by L = ∫[a to b] √(dx/dt)^2 + (dy/dt)^2 + (dz/dt)^2 dt.
Step 2: Compute the derivatives of each component of r(t). For r(t) = (6t, t^2, (1/9)t^3), calculate dx/dt, dy/dt, and dz/dt: dx/dt = 6, dy/dt = 2t, dz/dt = (1/3)t^2.
Step 3: Substitute the derivatives into the formula for the curve length. The integrand becomes √((dx/dt)^2 + (dy/dt)^2 + (dz/dt)^2) = √(6^2 + (2t)^2 + ((1/3)t^2)^2).
Step 4: Simplify the expression inside the square root. Combine terms: √(36 + 4t^2 + (1/9)t^4).
Step 5: Set up the definite integral for the curve length. Integrate L = ∫[0 to 1] √(36 + 4t^2 + (1/9)t^4) dt. Evaluate this integral to find the curve length.