Which of the following integrals correctly represents the area of the region enclosed by the curves , , and for ?
A
B
C
D
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1
Step 1: Understand the problem. We are tasked with finding the integral that represents the area of the region enclosed by the curves y = 4x, y = 16x, and y = 1/16x for x > 0. The integral should represent the difference between the upper curve and the lower curve over the specified interval.
Step 2: Analyze the curves and their relationships. For x > 0, y = 16x is the upper curve, and y = 1/16x is the lower curve in the region of interest. The area is calculated by subtracting the lower curve from the upper curve.
Step 3: Determine the interval of integration. The problem specifies that the correct integral is over the interval x = 0 to x = 1. This interval corresponds to the region where the curves y = 16x and y = 1/16x enclose the area.
Step 4: Set up the integral. The area is given by the integral of the difference between the upper curve and the lower curve over the interval x = 0 to x = 1. This can be expressed as:
Step 5: Verify the setup. The integral correctly represents the area of the region enclosed by the curves y = 16x and y = 1/16x over the interval x = 0 to x = 1. The subtraction ensures that the area is calculated as the difference between the upper and lower curves.