Recognize that the problem involves evaluating a logarithm: \( \log_9 \left( \frac{1}{81} \right) \).
Recall the property of logarithms that \( \log_b \left( \frac{1}{a} \right) = -\log_b(a) \). This means we can rewrite the expression as \( -\log_9(81) \).
Express 81 as a power of 9. Since \( 81 = 9^2 \), we can substitute this into the logarithm to get \( -\log_9(9^2) \).
Apply the power rule of logarithms, which states \( \log_b(a^c) = c \cdot \log_b(a) \). This simplifies our expression to \( -2 \cdot \log_9(9) \).
Since \( \log_9(9) = 1 \) (because any number to the power of 1 is itself), the expression simplifies to \( -2 \cdot 1 \).