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Ch. 1 - Functions
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243당신이 사용하는 게 아니라요?교과서 변경
1장, 문제 62

Simplify the difference quotient ƒ(x+h)-ƒ(x)/h
ƒ(x) = 10

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Step 1: Understand the function given, \( f(x) = 10 \). This is a constant function, meaning it does not change with different values of \( x \).
Step 2: Substitute \( f(x) \) and \( f(x+h) \) into the difference quotient formula. Since \( f(x) = 10 \), we have \( f(x+h) = 10 \) as well.
Step 3: Write the difference quotient: \( \frac{f(x+h) - f(x)}{h} = \frac{10 - 10}{h} \).
Step 4: Simplify the expression: \( \frac{10 - 10}{h} = \frac{0}{h} \).
Step 5: Recognize that \( \frac{0}{h} = 0 \) for any non-zero \( h \). Therefore, the simplified difference quotient is 0.

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주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Difference Quotient

The difference quotient is a formula used to calculate the average rate of change of a function over an interval. It is expressed as (ƒ(x+h) - ƒ(x)) / h, where h represents a small change in x. This concept is fundamental in calculus as it leads to the definition of the derivative, which measures the instantaneous rate of change.
추천 영상:
06:43
The Quotient Rule

Function Evaluation

Function evaluation involves substituting a specific value into a function to determine its output. In this case, with ƒ(x) = 10, the function returns a constant value regardless of the input x. Understanding how to evaluate functions is crucial for simplifying expressions like the difference quotient.
추천 영상:
가이드 코스
4:26
Evaluating Composed Functions

Limit Concept

The limit concept is central to calculus, particularly in defining derivatives. As h approaches zero in the difference quotient, the expression converges to the derivative of the function at a point. This concept helps in understanding how functions behave as inputs change infinitesimally, which is essential for analyzing continuity and differentiability.
추천 영상:
05:50
One-Sided Limits