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Ch. 1 - Functions
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243당신이 사용하는 게 아니라요?교과서 변경
1장, 문제 1.60

Solving equations Solve the following equations.


5(ˣ³) = 29

검증된 단계별 안내
1
Step 1: Start by isolating the term with the variable. Divide both sides of the equation by 5 to get x^3 = \(\frac{29}{5}\).
Step 2: To solve for x, take the cube root of both sides of the equation. This will give you x = \(\sqrt\)[3]{\(\frac{29}{5}\)}.
Step 3: Simplify the expression if possible. In this case, \(\sqrt\)[3]{\(\frac{29}{5}\)} is already in its simplest form.
Step 4: Consider the properties of cube roots. Remember that the cube root of a number can be positive or negative, but since we are dealing with real numbers, we focus on the principal (positive) root.
Step 5: Verify your solution by substituting x back into the original equation to ensure that both sides are equal.

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주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Exponential Equations

Exponential equations involve variables in the exponent, such as the equation 5(x³) = 29. To solve these equations, one typically isolates the exponential term and applies logarithmic functions to both sides, allowing for the extraction of the variable from the exponent.
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Logarithms

Logarithms are the inverse operations of exponentiation. They allow us to solve for the exponent in an equation. For example, if we have an equation in the form a^b = c, we can use logarithms to express b as log_a(c), which is essential for solving exponential equations.
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Algebraic Manipulation

Algebraic manipulation involves rearranging and simplifying equations to isolate the variable of interest. This includes operations such as addition, subtraction, multiplication, and division, as well as applying properties of equality to maintain balance in the equation while solving for the unknown.
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Determine Continuity Algebraically