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Ch. 10 - Sequences and Infinite Series
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243당신이 사용하는 게 아니라요?교과서 변경
10장, 문제 10.R.47

42–76. Convergence or divergence Use a convergence test of your choice to determine whether the following series converge.
∑ (from k = 1 to ∞)(7 + sin k) / k²

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Identify the given series: \( \sum_{k=1}^{\infty} \frac{7 + \sin k}{k^2} \). We want to determine if this series converges or diverges.
Note that \( \sin k \) is bounded between -1 and 1, so the numerator \( 7 + \sin k \) is bounded between 6 and 8. This means the terms behave roughly like \( \frac{\text{constant}}{k^2} \) for large \( k \).
Recall the p-series test: \( \sum_{k=1}^{\infty} \frac{1}{k^p} \) converges if \( p > 1 \). Here, since the denominator is \( k^2 \), which corresponds to \( p = 2 > 1 \), the series \( \sum \frac{1}{k^2} \) converges.
Use the Comparison Test by comparing \( \frac{7 + \sin k}{k^2} \) with \( \frac{8}{k^2} \) (since 8 is an upper bound for the numerator). Since \( \sum \frac{8}{k^2} \) converges, and \( 0 \leq \frac{7 + \sin k}{k^2} \leq \frac{8}{k^2} \), the original series converges by the Comparison Test.
Conclude that the series \( \sum_{k=1}^{\infty} \frac{7 + \sin k}{k^2} \) converges absolutely because it is bounded by a convergent p-series with \( p = 2 \).

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주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Convergence and Divergence of Infinite Series

An infinite series converges if the sum of its terms approaches a finite limit as the number of terms grows indefinitely. If the sum does not approach a finite value, the series diverges. Understanding this distinction is fundamental to analyzing series behavior.
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가이드 코스
06:52
Convergence of an Infinite Series

Comparison Test for Series Convergence

The Comparison Test involves comparing a given series to a second series whose convergence behavior is known. If the terms of the given series are smaller than those of a convergent series, it also converges. This test is useful when terms are positive and can be bounded.
추천 영상:
가이드 코스
09:25
Direct Comparison Test

Behavior of the p-Series

A p-series has the form ∑ 1/k^p and converges if and only if p > 1. Since the given series has terms involving 1/k², recognizing this helps determine convergence by comparing to a known convergent p-series with p=2.
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가이드 코스
04:30
P-Series and Harmonic Series