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Ch. 11 - Power Series
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243당신이 사용하는 게 아니라요?교과서 변경
11장, 문제 11.R.63

A differential equation Find a power series solution of the differential equation y'(x) - 4y + 12 = 0, subject to the condition y(0) = 4. Identify the solution in terms of known functions.

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1
Rewrite the differential equation in standard form: \(y'(x) = 4y - 12\).
Assume a power series solution of the form \(y(x) = \sum_{n=0}^{\infty} a_n x^n\) and find its derivative \(y'(x) = \sum_{n=1}^{\infty} n a_n x^{n-1}\).
Substitute the series expressions for \(y(x)\) and \(y'(x)\) into the differential equation to get \(\sum_{n=1}^{\infty} n a_n x^{n-1} = 4 \sum_{n=0}^{\infty} a_n x^n - 12\).
Align powers of \(x\) on both sides by shifting indices as needed, then equate coefficients of like powers of \(x\) to find a recurrence relation for the coefficients \(a_n\).
Use the initial condition \(y(0) = 4\) to find \(a_0\), then solve the recurrence relation to express \(y(x)\) as a power series and recognize it as a known function (likely involving exponentials).

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주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Power Series Solutions of Differential Equations

A power series solution expresses the unknown function as an infinite sum of powers of the variable, typically centered at a point like x=0. This method is useful when standard solution techniques are difficult, allowing the differential equation to be solved by determining the coefficients of the series.
추천 영상:
05:58
Intro to Power Series

Initial Conditions and Their Role

Initial conditions specify the value of the solution or its derivatives at a particular point, enabling the determination of arbitrary constants in the general solution. For example, y(0) = 4 fixes the constant term in the power series, ensuring the solution fits the given problem.
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가이드 코스
05:03
Initial Value Problems

Solving First-Order Linear Differential Equations

First-order linear differential equations have the form y' + p(x)y = q(x). They can be solved using integrating factors or by recognizing standard solution forms. Identifying the solution in terms of known functions often involves rewriting the equation and integrating accordingly.
추천 영상:
06:06
Solving Separable Differential Equations