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Ch. 2 - Limits
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243당신이 사용하는 게 아니라요?교과서 변경
2장, 문제 2.5.50

Determine limxf(x)\(\lim\)_{x\(\rightarrow\]\infty\)}f\(\left\)(x\(\right\)) and limxf(x)\(\lim\)_{x\(\rightarrow\)-\(\infty\)}f\(\left\)(x\(\right\)) for the following functions. Then give the horizontal asymptotes of ff (if any).


f(x)=4x(3x9x2+1)f\(\left\)(x\(\right\))=4x\(\left\)(3x-\(\sqrt{9x^2+1}\]\right\))

검증된 단계별 안내
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First, let's analyze the function f(x) = 4x(3x - \(\sqrt{9x^2 + 1}\)). We need to find the limits as x approaches infinity and negative infinity.
To find \(\lim\)_{x \(\to\) \(\infty\)} f(x), factor out x from the square root in the expression \(\sqrt{9x^2 + 1}\). This gives us \(\sqrt{x^2(9 + \frac{1}{x^2}\))} = x\(\sqrt{9 + \frac{1}{x^2}\)}.
Rewrite the function as f(x) = 4x(3x - x\(\sqrt{9 + \frac{1}{x^2}\)}) = 4x^2(3 - \(\sqrt{9 + \frac{1}{x^2}\)}).
As x approaches infinity, \(\frac{1}{x^2}\) approaches 0, so \(\sqrt{9 + \frac{1}{x^2}\)} approaches \(\sqrt{9}\) = 3. Therefore, the expression 3 - \(\sqrt{9 + \frac{1}{x^2}\)} approaches 0.
Thus, \(\lim\)_{x \(\to\) \(\infty\)} f(x) = 4x^2 \(\cdot\) 0 = 0. Similarly, for \(\lim\)_{x \(\to\) -\(\infty\)} f(x), the same reasoning applies, leading to the conclusion that the horizontal asymptote is y = 0.

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주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Limits at Infinity

Limits at infinity describe the behavior of a function as the input approaches positive or negative infinity. This concept is crucial for understanding how functions behave in extreme cases, allowing us to determine horizontal asymptotes. For example, if the limit of f(x) as x approaches infinity is a finite number, it indicates that the function approaches a horizontal line at that value.
추천 영상:
03:07
Cases Where Limits Do Not Exist

Horizontal Asymptotes

Horizontal asymptotes are lines that a graph approaches as x approaches infinity or negative infinity. They provide insight into the end behavior of a function. If a function has a horizontal asymptote at y = L, it means that as x becomes very large or very small, the function values get closer to L, indicating stability in the function's output at extreme values.
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5:50
Asymptotes of Hyperbolas

Dominant Terms in Functions

In polynomial and rational functions, the dominant term is the term with the highest degree, which significantly influences the function's behavior as x approaches infinity or negative infinity. Identifying the dominant term helps simplify the limit calculations, as lower-degree terms become negligible in comparison. For instance, in the function f(x) = 4x(3x - √(9x² + 1)), the dominant term is 12x², which guides the limit evaluation.
추천 영상:
05:44
Divergence Test (nth Term Test)