Evaluate each limit.

lim x→0+ 1−cos^2x / sin x

검증된 단계별 안내

Step 1: Recognize that the expression \(1 - \cos^2 x\) can be rewritten using the Pythagorean identity \(\sin^2 x + \cos^2 x = 1\). Therefore, \(1 - \cos^2 x = \sin^2 x\).

Step 2: Substitute \(\sin^2 x\) for \(1 - \cos^2 x\) in the limit expression. The limit now becomes \(\lim_{{x \to 0^+}} \frac{\sin^2 x}{\sin x}\).

Step 3: Simplify the expression \(\frac{\sin^2 x}{\sin x}\) by canceling one \(\sin x\) from the numerator and the denominator. This simplifies to \(\sin x\).

Step 4: Evaluate the limit \(\lim_{{x \to 0^+}} \sin x\). Since \(\sin x\) is continuous at \(x = 0\), you can directly substitute \(x = 0\) into \(\sin x\).

Step 5: Conclude the evaluation by noting that the limit of \(\sin x\) as \(x\) approaches 0 from the positive side is simply \(\sin(0)\).

비슷한 문제에 대한 검증된 영상 답변:

이 영상 해법은 위 문제에 도움이 된다고 튜터들이 추천한 것입니다.

영상 길이:

도움이 되었나요?

주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Limits

A limit is a fundamental concept in calculus that describes the behavior of a function as its input approaches a certain value. In this case, we are interested in the limit of the expression as x approaches 0 from the positive side (0+). Understanding limits is crucial for evaluating functions that may not be directly computable at specific points.

Trigonometric Functions

Trigonometric functions, such as sine and cosine, are periodic functions that relate angles to ratios of sides in right triangles. In the given limit, we encounter cos^2(x) and sin(x), which require knowledge of their properties and behaviors, especially near critical points like x = 0, where they can exhibit specific limits and values.

L'Hôpital's Rule

L'Hôpital's Rule is a method used to evaluate limits that result in indeterminate forms, such as 0/0 or ∞/∞. It states that if the limit of f(x)/g(x) leads to an indeterminate form, the limit can be found by taking the derivative of the numerator and the derivative of the denominator. This rule is particularly useful in simplifying complex limit problems involving trigonometric functions.

Evaluate each limit. lim x→0+ 1−cos^2x / sin x