Skip to main content
Ch. 2 - Limits
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243당신이 사용하는 게 아니라요?교과서 변경
2장, 문제 2.7.29

Use the precise definition of a limit to prove the following limits. Specify a relationship between ε and δ that guarantees the limit exists.
lim x→2 (x^2+3x)=10

검증된 단계별 안내
1
Step 1: Recall the precise definition of a limit. For the limit \( \lim_{x \to a} f(x) = L \) to hold, for every \( \varepsilon > 0 \), there must exist a \( \delta > 0 \) such that if \( 0 < |x - a| < \delta \), then \( |f(x) - L| < \varepsilon \).
Step 2: Identify the function \( f(x) = x^2 + 3x \), the point \( a = 2 \), and the limit \( L = 10 \). We need to show that for every \( \varepsilon > 0 \), there exists a \( \delta > 0 \) such that if \( 0 < |x - 2| < \delta \), then \( |(x^2 + 3x) - 10| < \varepsilon \).
Step 3: Simplify the expression \( |(x^2 + 3x) - 10| \). This becomes \( |x^2 + 3x - 10| \). Factor or simplify this expression to find a form that will help relate \( \varepsilon \) and \( \delta \).
Step 4: Consider the expression \( |x^2 + 3x - 10| \). Rewrite it as \( |(x - 2)(x + 5)| \). We need to ensure that \( |(x - 2)(x + 5)| < \varepsilon \) whenever \( 0 < |x - 2| < \delta \).
Step 5: Establish a relationship between \( \varepsilon \) and \( \delta \). Choose \( \delta \) such that \( |x + 5| \) is bounded when \( x \) is near 2. For instance, if \( |x - 2| < 1 \), then \( 1 < x < 3 \), so \( 6 < x + 5 < 8 \). Use this bound to find a suitable \( \delta \) in terms of \( \varepsilon \).

비슷한 문제에 대한 검증된 영상 답변:

이 영상 해법은 위 문제에 도움이 된다고 튜터들이 추천한 것입니다.
영상 길이:
4m
도움이 되었나요?

주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Limit Definition

The precise definition of a limit states that for a function f(x) to approach a limit L as x approaches a value a, for every ε > 0, there exists a δ > 0 such that if 0 < |x - a| < δ, then |f(x) - L| < ε. This formalism is essential for rigorously proving limits in calculus.
추천 영상:
05:50
One-Sided Limits

Epsilon-Delta Relationship

In the context of limits, the ε (epsilon) represents how close f(x) must be to the limit L, while δ (delta) represents how close x must be to the point a. Establishing a relationship between ε and δ is crucial for demonstrating that as x gets sufficiently close to a, f(x) will be within ε of L, thus proving the limit exists.
추천 영상:
05:53
Finding Differentials

Polynomial Functions

Polynomial functions, such as f(x) = x^2 + 3x, are continuous everywhere on their domain. This continuity implies that limits can often be evaluated by direct substitution. Understanding the behavior of polynomial functions helps in applying the limit definition effectively, especially when proving limits at specific points.
추천 영상:
6:04
Introduction to Polynomial Functions