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Ch. 3 - Derivatives
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243당신이 사용하는 게 아니라요?교과서 변경
3장, 문제 3.R.73

72–76. Tangent lines Find an equation of the line tangent to each of the following curves at the given point.


y = 3x³+ sin x; (0, 0)

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1
To find the equation of the tangent line, we need to determine the derivative of the function y = 3x³ + sin(x) to find the slope of the tangent line at the given point (0, 0).
Differentiate the function y = 3x³ + sin(x) with respect to x. The derivative of 3x³ is 9x², and the derivative of sin(x) is cos(x). Therefore, the derivative y' = 9x² + cos(x).
Evaluate the derivative at the given point x = 0 to find the slope of the tangent line. Substitute x = 0 into y' = 9x² + cos(x) to get the slope m = 9(0)² + cos(0).
The slope m at x = 0 is cos(0), which simplifies to 1. Therefore, the slope of the tangent line at the point (0, 0) is 1.
Use the point-slope form of the equation of a line, y - y₁ = m(x - x₁), where m is the slope and (x₁, y₁) is the point (0, 0). Substitute m = 1, x₁ = 0, and y₁ = 0 into the equation to find the equation of the tangent line.

비슷한 문제에 대한 검증된 영상 답변:

이 영상 해법은 위 문제에 도움이 된다고 튜터들이 추천한 것입니다.
영상 길이:
4m

주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Tangent Line

A tangent line to a curve at a given point is a straight line that touches the curve at that point and has the same slope as the curve at that point. The equation of the tangent line can be found using the point-slope form, which requires the slope of the curve at the point of tangency and the coordinates of that point.
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가이드 코스
05:13
Slopes of Tangent Lines

Derivative

The derivative of a function at a point measures the rate at which the function's value changes as its input changes. It is the slope of the tangent line to the curve at that point. To find the equation of the tangent line, we first compute the derivative of the function and evaluate it at the given point to obtain the slope.
추천 영상:

Point-Slope Form

The point-slope form of a linear equation is given by y - y₁ = m(x - x₁), where (x₁, y₁) is a point on the line and m is the slope. This form is particularly useful for writing the equation of a tangent line once the slope and the point of tangency are known, allowing for a straightforward construction of the line's equation.
추천 영상:
3:56
Slope-Intercept Form